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geniusboy [140]
3 years ago
11

Christian has a collection of 18 shark teeth.he identified them as 6 tiger shark teeth, 8 sand shark teeth,and the rest as bull

shark teeth. What does the ratio 6:8 represent in this situation.
Mathematics
2 answers:
dmitriy555 [2]3 years ago
8 0

Answer:

tiger shark teeth to sand shark teeth

agasfer [191]3 years ago
4 0

Answer:

the number of the tiger shark teeth to the number of the sand shark teeth

Step-by-step explanation:

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1/5(x+2)+2x=6x-10 what does x=
horsena [70]
X= 2.737 - look on the website "Tiger algebra for the answer by typing in the question
6 0
3 years ago
Find the lateral area of the cylinder.<br><br>Give your answer in the terms of pi.
Wewaii [24]
Hi there! 

The formula for the lateral area of a cylinder is LA = 2 x pi x r x h. (two times pi times radius times height) Using this formula, we can plug in the values and solve for the lateral area.

Plugging in the values: LA = 2 x pi x 7 x 9
Simplifying: LA = 2pi x 63
LA = 126pi yd^2

ANSWER:
The 4th option - 126pi yd^2

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
6 0
3 years ago
Find the sin in the triangle
Ierofanga [76]

Answer:

.324 or 18.9 degrees

Step-by-step explanation:

rule is

sine equals opposite over hypotenuse,

cosine equals adjacent over hypotenuse, and

tangent equals opposite over adjacent

OR

soh cah toa

sine = soh = 12/37 = .324

arcsin(.324) or sin^-1(.324) in DEGREES not radians =

18.9 degrees

6 0
3 years ago
Can sides of a triangle have lengths 1, 13, and 14 ???
victus00 [196]

Answer: Yes it can!

Step-by-step explanation:

This is called a scalene triangle, where all 3 sides are different lengths.

5 0
3 years ago
Solve for X<br><br> PLEASE HELP ME
guapka [62]

Answer:

x = 10°

Step-by-step explanation:

Step 1:

92° + x° + 78° = 180°             Supplementary Angles

Step 2:

x° + 170° = 180°         Combine Like Terms

Step 3:

x° = 180° - 170°       Subtract 170° on both sides

Answer:

x = 10°

Hope This Helps :)

4 0
3 years ago
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