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Orlov [11]
3 years ago
8

Is the flame coloration a test for the metal or for nitrate ion?

Chemistry
2 answers:
maxonik [38]3 years ago
7 0

Answer:

The correct answer is metal.

Explanation:

The flame test is an analytical method used in chemistry to detect the presence of certain elements, mainly metal ions, based on the characteristic emission spectrum of each element. The color of the flame can also depend on temperature, identify the unknown element or simply a metallic ion based on its characteristics when emitting light.

Have a nice day!

mel-nik [20]3 years ago
5 0

Metallic ion because the metallic ions will enter an exited state and release photons energy, in the form of light, as they return to their ground state.

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Argon has a pressure of 34.6 atm. It is transferred to a new tank with a volume of 456 L and pressure of 2.94 atm. What was the
NemiM [27]

Answer:

38.75 L

Explanation:

From the question,

Applying Boyles Law,

PV = P'V'....................... Equation 1

Where P = Original pressure of the Argon gas, V = Original Volume of Argon gas, P' = Final pressure of Argon gas, V' =  Final Volume of Argon gas.

make V the subject of the equation

V = P'V'/P.................... Equation 2

Given: P = 34.6 atm, V' = 456 L, P' = 2.94 atm.

Substitute these values into equation 2

V = (456×2.94)/34.6

V = 38.75 L

3 0
3 years ago
How many valence electrons does Nitrogen have?​
irinina [24]

Answer:

5 valence electrons

Nitrogen has a total of 5 valence electrons

Explanation:

6 0
3 years ago
Write the advantages of molecular formula​
dusya [7]

Answer:

Its main advantage is <em>they information fits on one line of text</em> <u>(thus works well when using the formula in paragraphs)</u>. Disadvantages are <em>they can be confusing for larger molecules</em>

<em />

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8 0
2 years ago
Will give brainliest
madreJ [45]

Answer:

C

Explanation:

The concept behind, is mole ratio of Al:FeO

5 0
3 years ago
Use the given half reactions to "construct" an electrolytic cell. Zn^2+ + 2 e^---------&gt;Zn E°cell = -0.76 V Cu^2+ + 2 e^-----
Neko [114]

Answer:

See explanation and image attached

Explanation:

The standard cell potential at 298 K is given by;

E°cathode - E°anode

Hence;

E°cell = 0.34 V - (-0.76 V)

E°cell = 0.34 V + 0.76 V

E°cell = 1.1 V

To reduce Zn^2+ to Zn then Zn must be the cathode, hence;

E°cell = (-0.76 V) - 0.34 V

E°cell = -1.1 V

5 0
3 years ago
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