1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
slavikrds [6]
3 years ago
10

98 POINTS!

Chemistry
2 answers:
MatroZZZ [7]3 years ago
4 0
Rocks. Because the air water and soil are part of carbon.
tester [92]3 years ago
3 0
Air contains carbon dioxide (CO2)
soil and rocks may have carbonate (CO3)

so only water is not a source of carbon

You might be interested in
Why do covalent bonds not involve the transfer of electrons
zhannawk [14.2K]
Covalent bonds do not involve electron transfer because in covalent bonds, the electrons are shared between the atoms to form the molecule rather than being transferred to form ions as it is in the case of ionic bonds.<span />
6 0
3 years ago
Read 2 more answers
What are the half-reactions for a galvanic cell with aluminum and gold electrodes?
pashok25 [27]

Answer:B is right

Explanation: Al loses electrons and is oxidised, Au gains electron. And is reduced

4 0
3 years ago
Consider the reaction Mg(s) + I2 (s) → MgI2 (s) Identify the limiting reagent in each of the reaction mixtures below:
Lapatulllka [165]

Answer:

a) Nor Mg, neither I2 is the limiting reactant.

b) I2 is the limiting reactant

c) <u>Mg is the limiting reactant</u>

<u>d) Mg is the limiting reactant</u>

<u>e) Nor Mg, neither I2 is the limiting reactant.</u>

<u>f) I2 is the limiting reactant</u>

<u>g) Nor Mg, neither I2 is the limiting reactant.</u>

<u>h) I2 is the limiting reactant</u>

<u>i) Mg is the limiting reactant</u>

Explanation:

Step 1: The balanced equation:

Mg(s) + I2(s) → MgI2(s)

For 1 mol of Mg we need 1 mol of I2 to produce 1 mol of MgI2

a. 100 atoms of Mg and 100 molecules of I2

We'll have the following equation:

100 Mg(s) + 100 I2(s) → 100MgI2(s)

This is a stoichiometric mixture. <u>Nor Mg, neither I2 is the limiting reactant.</u>

b. 150 atoms of Mg and 100 molecules of I2

We'll have the following equation:

150 Mg(s) + 100 I2(s) → 100 MgI2(s)

<u>I2 is the limiting reactant</u>, and will be completely consumed. There will be consumed 100 Mg atoms. There will remain 50 Mg atoms.

There will be produced 100 MgI2 molecules.

c. 200 atoms of Mg and 300 molecules of I2

We'll have the following equation:

200 Mg(s) + 300 I2(s) →200 MgI2(s)

<u>Mg is the limiting reactant</u>, and will be completely consumed. There will be consumed 200 I2 molecules. There will remain 100 I2 molecules.

There will be produced 200 MgI2 molecules.

d. 0.16 mol Mg and 0.25 mol I2

We'll have the following equation:

Mg(s) + I2(s) → MgI2(s)

<u>Mg is the limiting reactant</u>, and will be completely consumed. There will be consumed 0.16 mol of I2. There will remain 0.09 mol of I2.

There will be produced 0.16 mol of MgI2.

e. 0.14 mol Mg and 0.14 mol I2

We'll have the following equation:

Mg(s) + I2(s) → MgI2(s)

This is a stoichiometric mixture. <u>Nor Mg, neither I2 is the limiting reactant.</u>

There will be consumed 0.14 mol of Mg and 0.14 mol of I2. there will be produced 0.14 mol of MgI2

f. 0.12 mol Mg and 0.08 mol I2

We'll have the following equation:

Mg(s) + I2(s) → MgI2(s)

<u>I2 is the limiting reactant</u>, and will be completely consumed. There will be consumed 0.08 moles of Mg. There will remain 0.04 moles of Mg.

There will be produced 0.08 moles of MgI2.

g. 6.078 g Mg and 63.455 g I2

We'll have the following equation:

Mg(s) + I2(s) → MgI2(s)

Number of moles of Mg = 6.078 grams / 24.31 g/mol = 0.250 moles

Number of moles I2 = 63.455 grams/ 253.8 g/mol = 0.250 moles

This is a stoichiometric mixture. <u>Nor Mg, neither I2 is the limiting reactant.</u>

There will be consumed 0.250 mol of Mg and 0.250 mol of I2. there will be produced 0.250 mol of MgI2

h. 1.00 g Mg and 2.00 g I2

We'll have the following equation:

Mg(s) + I2(s) → MgI2(s)

Number of moles of Mg = 1.00 grams / 24.31 g/mol = 0.0411 moles

Number of moles I2 = 2.00 grams/ 253.8 g/mol = 0.00788 moles

<u>I2 is the limiting reactant</u>, and will be completely consumed. There will be consumed 0.00788 moles of Mg. There will remain 0.03322 moles of Mg.

There will be produced 0.00788 moles of MgI2.

i. 1.00 g Mg and 2.00 g I2

We'll have the following equation:

Mg(s) + I2(s) → MgI2(s)

Number of moles of Mg = 1.00 grams / 24.31 g/mol = 0.0411 moles

Number of moles I2 = 20.00 grams/ 253.8 g/mol = 0.0788 moles

<u>Mg is the limiting reactant</u>, and will be completely consumed. There will be consumed 0.0411 moles of Mg. There will remain 0.0377 moles of I2.

There will be produced 0.0411 moles of MgI2.

4 0
3 years ago
A compound is 79.94g carbon, 26.82g hydrogen, and 93.24g nitrogen. What is the empirical formula?
Pani-rosa [81]

Answer:

i dont know

Explanation:

sorry

5 0
3 years ago
The picture is above^ someone help me please :)
Ronch [10]

Answer:

idk plz do not report

Explanation:

8 0
3 years ago
Other questions:
  • Which atomic model describes the atom as a nucleus surrounded by electrons that travel as waves in the electron cloud? (4 points
    10·1 answer
  • Arab cultures charted planets in the Dark Ages. Europeans helped establish the Sun-centered model of the solar system during the
    14·1 answer
  • A repeating unit in all organic compounds are called
    12·1 answer
  • How many moles of solute would be needed to form two liters of a one molar
    11·1 answer
  • At constant pressure, which of these systems do work on the surroundings? Check all that apply.
    6·1 answer
  • How many significant figure are in the number 0.000850320
    5·1 answer
  • Kamal was told by his mother to pour water through a thin cloth into another container to further purify the water.
    8·1 answer
  • JOIN MY AMONG US GAME TELL ME IF YOU JOIN THE CODE IS QUVNDF PLEASE JOIN
    13·2 answers
  • What happens to the molecules that make up a chocolate chip as it is heated in the oven?​
    12·2 answers
  • you have a sample of.neon gas that you want to use to.make a glowing sign. you investigate that the gas sample is at 45c and has
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!