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VARVARA [1.3K]
3 years ago
14

If the moles and volume of a gas are held constant, dropping the temperature from 40 degrees Celsius to 20 degrees Celsius cause

s would cause an initial pressure of 3 atmospheres to drop to 1.5 atmospheres.
T/F
Chemistry
2 answers:
evablogger [386]3 years ago
8 0
It would cause a drop <span>but I am not sure  double check other answers </span>
mixer [17]3 years ago
5 0

Answer:

False.

Explanation:

Hello,

In this case, as the moles are held constant, one uses the Gay-Lussac's law in order to relate both the temperature and the pressure at the beginning and at the end of the experiment via the following relationship:

P_1T_2=P_2T_1

By solving for the pressure at the second (final) state we can substantiate whether the 1.5 atm are correct as shown below:

P_2=\frac{P_1T_2}{T_1}=\frac{3atm*293.15K}{313.15K}= 2.8 atm

Therefore, even when the pressure is correctly decreased, the given value is wrong as 2.8 atm is the correct final pressure, in this manner, the statement is false.

Best regards.

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Hydrazine (N 2 H 4 )) a rocket fuel reacts with oxygen to form nitrogen gas and water vapor . The reaction is represented with t
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The mass of hydrazine (N₂H₄) required to produce 96 g of water (H₂O) is 85.4 g (Option C)

<h3>Balanced equation </h3>

N₂H₄ + O₂ —> N₂ + 2H₂O

Molar mass of N₂H₄ = (2×14) + (4×1) = 32 g/mol

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SUMMARY

From the balanced equation above,

36 g of H₂O were produced by 32 g of N₂H₄

<h3>How to determine the mass of N₂H₄</h3>

From the balanced equation above,

36 g of H₂O were produced by 32 g of N₂H₄

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Learn more about stoichiometry:

brainly.com/question/14735801

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