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VARVARA [1.3K]
3 years ago
14

If the moles and volume of a gas are held constant, dropping the temperature from 40 degrees Celsius to 20 degrees Celsius cause

s would cause an initial pressure of 3 atmospheres to drop to 1.5 atmospheres.
T/F
Chemistry
2 answers:
evablogger [386]3 years ago
8 0
It would cause a drop <span>but I am not sure  double check other answers </span>
mixer [17]3 years ago
5 0

Answer:

False.

Explanation:

Hello,

In this case, as the moles are held constant, one uses the Gay-Lussac's law in order to relate both the temperature and the pressure at the beginning and at the end of the experiment via the following relationship:

P_1T_2=P_2T_1

By solving for the pressure at the second (final) state we can substantiate whether the 1.5 atm are correct as shown below:

P_2=\frac{P_1T_2}{T_1}=\frac{3atm*293.15K}{313.15K}= 2.8 atm

Therefore, even when the pressure is correctly decreased, the given value is wrong as 2.8 atm is the correct final pressure, in this manner, the statement is false.

Best regards.

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Given :

Number of He atoms, n = 3.4\times 10^{24} atoms.

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How many grams are their in given number of He atoms.

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Let, number of gram He in 3.4\times 10^{24} atoms is x , so :

x = \dfrac{3.4\times 10^{24}}{6.022\times 10^{23}}\times 4\\\\x =  $$22.58\ g

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What is the molarity of a 0.65L solution containing 63 grams of ? The molar mass of NaCl is 58.44 g/mol
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Explanation:

The molarity of a solution is defined like the number of moles of solute per liters of solution.

molarity = moles of solute/(volume of solution in L)

We know the volume of solution in L.

volume of solution = 0.65 L

To go from the mass of our solute in grams to moles we have to use its molar mass.

mass of NaCl = 63 g

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