The mass of carbon required to produce iron from 5 67 g iron (iii) oxide is 9.0 g.
<h3>What is the mass of carbon required to produce iron from iron (iii) oxide?</h3>
The mass of carbon required to produce iron from iron (iii) oxide is determined from the equation of the reaction.
From the given equation of reaction, 3 moles of carbon produces 4 moles of iron.
- Moles of a substance = mass/molar mass
Molar mass of iron = 56.0 g
molar mass of carbon = 12.0 g
Moles of iron in 5.67 g of iron = 5.67/56 = 0.1 moles
Moles of carbon required = 3/4 × 0.1 = 0.75 moles
Mass of carbon = 0.75 × 12 = 9.0 g
Therefore, the mass of carbon required to produce iron from 5 67 g iron (iii) oxide is 9.0 g.
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