Question

For the reaction 8 H 2 S ( g ) − ⇀ ↽ − 8 H 2 ( g ) + S8 ( g ) 8H2S(g)↽−−⇀8H2(g)+S8(g) the equilibrium concentrations were found to be [ H 2 S ] = 0.250 M, [H2S]=0.250 M, [ H 2 ] = 0.600 M, [H2]=0.600 M, and [ S 8 ] = 0.750 M. [S8]=0.750 M. What is the equilibrium constant for this reaction

Answer 1

Answer:

Kc = 826

Explanation:

For the equilibrium:

8 H₂S (g)        ⇄   8 H₂(g)   + S₈ (g)

the equilibrium constant is:

Kc = [ H₂ ] ⁸ x [ S₈ ] /  [H₂S]⁸

Kc = 0.600⁸ x 0.750 / (0.250)⁸ = 1.68 x 10⁻² x 0.750 / 1.53 x 10⁻⁵

                                                =  824

Be careful with raising to the power of 8 in your calculator.