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matrenka [14]
3 years ago
10

A swimming-pool worker wants the pool's pH to be 7.2. She comes by to test the water and finds that the pH is 6.2. What should s

he do to correct this situation?
A. Do nothing.
B. Add water.
C. Add acid.
D. Add base
Chemistry
1 answer:
vichka [17]3 years ago
5 0
The swimming pools pH is below 7, meaning it is slightly acidic. If you want to make the pH higher, you must add a base which by definition has a pH higher than 7.

D. Add base
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An element has an atmomic number of 68. The number of protons and electron in a neutral atom of the element are?
Bess [88]

Answer:

Explanation:

An element whose atomic number is 68 (number Z), has 68 electrons and 68 protons. According to the periodic table it corresponds to the element Erbium (Er), whose mass number (A) is 167. The number of neutrons is 167-68 = 99.

8 0
4 years ago
Explain why a coin is able float on top of the water
arsen [322]
Because of the surface tention.
7 0
3 years ago
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A container of gas has a pressure of 3.4 atm at 30 ° C. If the gas is compressed to 1.5 atm, what is the new temperature?
Svetlanka [38]

Answer:

13.2 centigred due to that pressure

3 0
3 years ago
How would you prepare 1.00 L of a 0.400M solution of copper(II)sulfate, CuSO4?
Ber [7]
We need to dilute 0.400 mol of copper (II) sulfate, how do we know, how many weigh of CuSO_4 we have to dilute??

It's simple.

\eta=\frac{m}{MM}

Using a periodic table we can find the molar mass of Cu,~~S~~and~~O

MM_{CuSO_4}=153.9~g/mol

Then

m=\eta*MM

now we can replace it

m=0.400*159.6

\boxed{\boxed{m=63.84~g}}

Then we have to dilute 63.84 grams of copper (II) sulfate in 1 L of water to obtain a solution with 0.400M
3 0
3 years ago
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The area of a telescope lens is 7903 rnrn2 {a) What is the area in square feet (ft2)? (b) If it takes a technician 45 s to polis
LekaFEV [45]

Answer:

Area is 0.08504ft^{2} and 2.6\times 10^{3}s are needed for polishing

Explanation:

(a) ft is unit of F.P.S system whether mm is unit of M.K.S system.

According to unit conversion, 1mm=0.00328ft

So, 1mm^{2}=(0.00328)^{2}ft^{2}=1.076\times 10^{-5}ft^{2}

hence, 7903mm^{2}=7903\times 1.076\times 10^{-5}ft^{2}=0.08504ft^{2}

So, area of telescope lens is 0.08504ft^{2}

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So, 7903mm^{2} are polished in \frac{45\times 7903}{135}s or 2.6\times 10^{3}s

5 0
3 years ago
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