Answer:
2NaOH + H2So4 》Na2So4+ 2H2O
Explanation:
SODIUM HYDROXIDE, 2NaOH IS (aq)
FULFURIC ACID, H2So4 IS (aq)
SODIUM SULFATE, Na2So4 IS (aq)
WATER,2H20 IS (l)
Answer:
2KBr + MgF₂ –> 2KF + MgBr₂
The coefficients are: 2, 1, 2, 1
Explanation:
KBr + MgF₂ –> KF + MgBr₂
The above equation can be balance as illustrated below:
KBr + MgF₂ –> KF + MgBr₂
There are 2 atoms of F on the left side and 1 atom on the right. It can be balance by writing 2 before KF as shown below:
KBr + MgF₂ –> 2KF + MgBr₂
There 2 atoms of K on the right side and 1 atom on the left side. It can be balance by writing 2 before KBr as shown below:
2KBr + MgF₂ –> 2KF + MgBr₂
Now, the equation is balanced.
The coefficients are: 2, 1, 2, 1
Answer:
C. Electron-negative charge
Explanation:
The electron is subatomic particle that revolve around outside the nucleus and has negligible mass. It has a negative charge.
Symbol= e⁻
Mass= 9.10938356×10³¹Kg
It was discovered by j. j. Thomson in 1897 during the study of cathode ray properties.
He constructed the glass tube and create vacuum in it. He applied electric current between electrodes. He noticed that a ray of particles coming from cathode to wards positively charged anode. This ray was cathode ray.
Properties of cathode ray:
The ray is travel in straight line.
The cathode ray is independent of composition of cathode.
When electric field is applied cathode ray is deflected towards the positively charged plate.
Hence it was consist of negatively charged particles.
While neutron and proton are present inside the nucleus. Proton has positive charge while neutron is electrically neutral. Proton is discovered by Rutherford while neutron is discovered by James Chadwick in 1932.
Symbol of proton= P⁺
Symbol of neutron= n⁰
Mass of proton = 1.672623×10⁻²⁷ Kg
Mass of neutron = 1.674929×10⁻²⁷ Kg
An atom consist of electron, protons and neutrons. Protons and neutrons are present with in nucleus while the electrons are present out side the nucleus.
All these three subatomic particles construct an atom.
Answer:-
27.38%
Explanation:-
Molecular weight of sodium hydrogen carbonate NaHCO3
= 23 x 1 + 1 x 1 + 12 x 1 + 16 x 3
= 84 gram
Total sodium Na present in NaHCO3 = 23 x 1 = 23 gram
Percentage of sodium present=
Total sodium x 100/ (Total molecular weight)
= 23 x 100 / 84
= 27.38 %
