Answer:
14.25
Step-by-step explanation:
85.50 devided by 6 = 14.25
The given equation has no solution when K is any real number and k>12
We have given that
3x^2−4x+k=0
△=b^2−4ac=k^2−4(3)(12)=k^2−144.
<h3>What is the condition for a solution?</h3>
If Δ=0, it has 1 real solution,
Δ<0 it has no real solution,
Δ>0 it has 2 real solutions.
We get,
Δ=k^2−144 here Δ is not zero.
It is either >0 or <0
Δ<0 it has no real solution,
Therefore the given equation has no solution when K is any real number.
To learn more about the solution visit:
brainly.com/question/1397278
Answer:
Step-by-step explanation:
g(-4) = 4 , x < -2
g(-2) = (x - 1)² ; -2≤x< 1
= (-2-1)²
= (-3)²
g(-2) = 9
g(0) = (x -1)² ; -2 ≤ x < 1
= (0 -1)²
= (-1)²
= 1
