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3 years ago

NEED HELP ASAP PLEASE Atoms join with other atoms by bonding with them in order to become as chemically________ as possible.

Chemistry

2 answers:

Natalija [7]3 years ago

4 0

C. Stable for sure.

Sveta_85 [38]3 years ago

3 0

It will be C- stable if you think about it because..

When they bond with others they are not going to become chemically unstable...

Inert means unreactive and that doesn't really matter in this situation

Electrified doesn't really matter in this instance

The most logical is stable.

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What is the formula of the compounds Cl- and Na+

Whitepunk [10]

Na and Cl together form the compound
NaCl2

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3 years ago

a 25.5 liter balloon holding 3.5 moles of carbon dioxide leaks. If we are able to determine that 1.9 moles of carbon dioxide esc

kap26 [50]

Answer:

11.66 L.

Explanation:

We can use the general law of ideal gas: PV = nRT.

where, P is the pressure of the gas in atm.

V is the volume of the gas in L.

n is the no. of moles of the gas in mol.

R is the general gas constant,

T is the temperature of the gas in K.

If P and T are constant, and have different values of n and V:

(V₁n₂) = (V₂n₁).

V₁ = 25.5 L, n₁ = 3.5 mol.

V₂ = ??? L, n₂ = 3.5 mol - 1.9 mol = 1.6 mol.

∴ V₂ = (V₁n₂)/(n₁) = (25.5 L)(1.6 mol)/(3.5 mol) = 11.66 L.

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3 years ago

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Wch of the following phrases is the best definition of science?

krek1111 [17]

Answer: A i think

Explanation:

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3 years ago

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sample of carbon monoxide gas occupies 3.20 L at 125 °C. At what temperature will the gas occupy a volume of 1.54 L if the press

Anna [14]

Answer:

-81.5 degrees C or 191.5 K

Explanation:

We want to use Charles' gas law: V/T = V/T

Our initial volume is 3.20 L, and our initial temperature is 125 degrees C, or 125 + 273 = 398 degrees Kelvin.

Our new Volume is 1.54 L, but we don't know what the temperature is. So, we use the equation:

3.20 L / 398 K = 1.54 L / T ⇒ Solving for T, we get: T = 191.5 K

If we want this in degrees Celsius, we subtract 273: 191.5 - 273 = -81.5 degrees C

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3 years ago

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An unknown compound with a molar mass of 223.94 g/mol consists of 32.18% c, 4.50% h, and 63.32% cl. find the molecular formula f

Dima020 [189]

The actual number of atoms of each element present in the molecule of the compound is represented by the formula known as molecular formula.

Molar mass of the unknown compound = 223.94 g/mol (given)

Mass of each element present in the unknown compound is determined as:

Mass of carbon, $C$ :

$\frac{32.18}{100}\times 223.94 = 72.06 g$

Mass of hydrogen, $H$ :

$\frac{4.5}{100}\times 223.94 = 10.08 g$

Mass of chlorine, $Cl$ :

$\frac{63.32}{100}\times 223.94 = 141.79 g$

Now, the number of each element in the unknown compound is determined by the formula:

$number of moles = \frac{given mass}{molar mass}$

Number of moles of $C$ :

$number of moles = \frac{72.06}{12} = 6.005 mole\simeq 6 mole$

Number of moles of $H$ :

$number of moles = \frac{10.08}{1} = 10.08 mole\simeq 10 mole$

Number of moles of $Cl$

$number of moles = \frac{141.79}{35.5} = 3.99 mole\simeq 4 mole$

Dividing each mole with the smallest number of mole, to determine the empirical formula:

$C_{\frac{6}{4}}H_{\frac{10}{4}}Cl_{\frac{10}{4}}$

$C_{1.5}H_{2.5}Cl_{1}$

Multiplying with 2 to convert the numbers in formula into a whole number:

So, the empirical formula is $C_{3}H_{5}Cl_{2}$ .

Empirical mass = $12\times 3+1\times 5+2\times 35.5 = 112 g/mol$

In order to determine the molecular formula:

n = $\frac{molar mass}{empirical mass}$

n = $\frac{223.94}{112} = 1.99 \simeq 2$

So, the molecular formula is:

$2\times C_{3}H_{5}Cl_{2} = C_{6}H_{10}Cl_{4}$

6 0

3 years ago