Answer:
Please find the complete solution in the attached file.
Explanation:
If I touch a hot object, my hand gets hot through which type of heat transfer?
2 answers:
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Im taking lambda as x (wavelength)
m = 0.17 kg
v=37m/s
h=6.62*10^-34m²kg/s
x= h/mv
m = 0.17 kg
v=37m/s
h=6.62*10^-34m²kg/s
x= h/mv
Answer:
Explanation:
2NO₂ ⇌ N₂O₄
E/mol·L⁻¹: 0.058 0.012
K_{\text{eq}} = \dfrac{\text{[N$_{2}$O$_{4}$]}}{\text{[NO$_{2}$]$^{2}$}} = \dfrac{0.012}{0.058^{2}} = \mathbf{3.6} \\\\
\text{The $K_{\text{eq}}$ value would be $\boxed{\mathbf{3.6}}$}