Hello!
Three nails have a mass of 3.05 g. How many moles of iron do they contain?
Data:
3 nails of iron = 3.05 g (by nail)
The atomic mass of iron is 55.845 amu, so the molar mass is:
M = 55.845 → M ≈ 56 g / mol
With a simple 3 rule:
56 g → 1 mol
3.05 g → y mol
Therefore:
Soon:
3 nails → 3*0.05446 = 0.1638 moles (answer)
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I Hope this helps, greetings ... Dexteright02! =)
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Hope this helps!
Answer:
Explanation:sheesh baby monkey omah
Answer: (2)3.0 mol
Explanation: 222.3g= 222.3/74= 3.0 mol
1mol Ca(OH)2 is 74g
Answer:
a. 100.0 mL of 0.10 M NH₃ with 100.0 mL of 0.15 M NH₄Cl.
c. 50.0 mL of 0.15 M HF with 20.0 mL of 0.15 M NaOH.
Explanation:
A buffer system is formed in 1 of 2 ways:
- A weak acid and its conjugate base.
- A weak base and its conjugate acid.
Determine whether mixing each pair of the following results in a buffer.
a. 100.0 mL of 0.10 M NH₃ with 100.0 mL of 0.15 M NH₄Cl.
YES. NH₃ is a weak base and NH₄⁺ (from NH₄Cl ) is its conjugate base.
b. 50.0 mL of 0.10 M HCl with 35.0 mL of 0.150 M NaOH.
NO. HCl is a strong acid and NaOH is a strong base.
c. 50.0 mL of 0.15 M HF with 20.0 mL of 0.15 M NaOH.
YES. HF is a weak acid and it reacts with NaOH to form NaF, which contains F⁻ (its conjugate base).
d. 175.0 mL of 0.10 M NH₃ with 150.0 mL of 0.12 M NaOH.
NO. Both are bases.
