Question

a sample of the hydrate of sodium carbonate has a mass of 8.85 g. it loses 1.28 g when heated. find the molar ratio of this compound and classify the type of hydrate.

Answer 1

Answer:

Molar ratio of the compound is 1:1 and the type of hydrate is Mono hydrate.

Explanation:

From the given,

Mass of sodium carbonate $Na_{2}CO_{3}.XH_{2}O$ = 8.85 g

Loss mass $H_{2}O$ = 1.28 g

Actual weight of sodium carbonate = 8.85 g - 1.28 g = 7.57 g

$7.57 g Na_{2}CO_{3} \times \frac{1mol}{106 g} =\frac{0.0714}{0.0714}=1$

$1.28g H_{2}O \times \frac{1mol}{18 g} =\frac{0.0711}{0.0714}=1$

Therefore, the compound has only one water molecule.

Molecular formula of the compound is $Na_{2}CO_{3}.H_{2}O$ an name of the compound is sodium carbonate mono hydrate.

Hence, the type of the compound is Mono hydrate.