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MaRussiya [10]
4 years ago
9

answer the following question by entering the numeric value with appropriate units. if the length of one side of a square is 12.

0 m, what is the perimeter of the square?
Chemistry
1 answer:
Tasya [4]4 years ago
8 0
Using the length given '12 m', because the shape of the object is a square all sides are congruent. 
Basically 12+12+12+12=48 or 12 x 4= 48
The answer is 48 m
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Convert 4.50 moles of Fe to atoms of Fe
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Each mole of a substance contains 6.02 x 10²³ particles
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3 years ago
10. A small gold nugget has volume of 0.87 cm3. What is its mass if the density of gold is 19.3 g/cm3?
bulgar [2K]

Answer:

16.791 grams

Explanation:

The density formula is:

d=\frac{m}{v}

Rearrange the formula for m, the mass. Multiply both sides of the equation by v.

d*v=\frac{m}{v}*v

d*v=m

The mass of the gold nugget can be found by multiplying the density and volume. The density is 19.3 grams per cubic centimeter and the volume is 0.87 cubic centimeters.

d= 19.3 g/cm^3\\v-0.87 cm^3

Substitute the values into the formula.

m=d*v

m= 19.3 g/cm^3*0.87 cm^3

Multiply. Note that the cubic centimeters, or cm³ will cancel each other out.

m=19.3 g*0.87

m=16.791 g

The mass of the gold nugget is 16.791 grams.

8 0
3 years ago
How many kPa are in 2,150 mmHg?<br> 2.83 kPa<br> 287 kPa<br> 1.61 ´ 104 kPa<br> 2.18 ´ 105 kPa
vlabodo [156]

Answer:

2150 mmHg ( 1 atm / 760 mmHg ) ( 101.325 kPa / 1 atm ) = 286.643 kPa

Therefore, the closest value from the choices is the second one which has the value of 287, this would be answer.

Explanation:

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What is the oxidation state of S in so ??​
Marina86 [1]

Answer:

+2

Explanation:

If a compound SO existed, we would identify the oxidation state of sulfur using the following logic:

  • oxygen is more electronegative than sulfur, so it's more electron-withdrawing and it should have a negative oxidation state producing a positive oxidation state for sulfur;
  • oxygen typically has an oxidation state of -2;
  • we may then apply the fact that SO is expected to be a molecule with a net charge of 0;
  • if the net charge is 0 and the oxidation state of oxygen is -2, we may set the oxidation state of S to x;
  • write the equation for the net charge of 0 by adding all individual charges of the two atoms: x + (-2) = 0;
  • hence, x = 2.

That said, in this hypothetical compound S would have an oxidation state of +2.

6 0
3 years ago
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