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3 years ago

What is the mass of 1.7 × 1023 atoms of zinc (Zn)?

Chemistry

2 answers:

elena55 [62]3 years ago

7 0

Answer : The mass of zinc is 18.3 grams.

Explanation :

First we have to calculate the moles of zinc.

As, $6.022\times 10^{23}$ number of zinc atoms present in 1 mole of zinc

So, $1.7\times 10^{23}$ number of zinc atoms present in $\frac{1.7\times 10^{23}}{6.022\times 10^{23}}=0.28$ mole of zinc

Now we have to calculate the mass of zinc.

Molar mass of zinc = 65.4 g/mole

$\text{Mass of }Zn=\text{Moles of }Zn\times \text{Molar mass of }Zn$

$\text{Mass of }Zn=0.28mole\times 65.4g/mole=18.3g$

Therefore, the mass of zinc is 18.3 grams.

ycow [4]3 years ago

4 0

1 mol Zn 65.41 g Zn
1.7 x10^23 atoms Zn x --------------- x ------------- = 18.47 g Zn
6.022 x 10^23 atoms 1 mol Zn

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How much energy is needed to vaporize 75.0 g of diethyl ether (c4h10o) at its boiling point (34.6°c), given that δhvap of diethy

malfutka [58]

Answer: 26.8 kJ of energy is needed to vaporize 75.0 g of diethyl ether

Explanation:

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4 years ago

How does the temperature of absolute zero relate to the kinetic energy of a substance's molecules?

skelet666 [1.2K]

Answer:

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Explanation:

8 0

3 years ago

Can someone find the independent variable and the dependent variable ?

Tatiana [17]

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3 years ago

How many different kinds of monomers are there in starch?

Levart [38]

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4 years ago

Sulfur and oxygen form both sulfur dioxide and sulfur trioxide. When samples of these are decomposed, the sulfur dioxide produce

bezimeni [28]

Answer:

For A: The mass of oxygen per gram of sulfur for sulfur dioxide is 0.997 g

For B: The mass of oxygen per gram of sulfur for sulfur trioxide is 1.5 g

Explanation:

For A:

The chemical equation for decomposition of sulfur dioxide follows:

$SO_2\rigtarrow S+O_2$

We are given:

Mass of sulfur = 3.47 g

Mass of oxygen = 3.46 g

To calculate the mass of oxygen per gram of sulfur, we apply unitary method:

For every 3.47 g of sulfur, 3.46 g of oxygen will form.

So, for 1 gram of sulfur, $\frac{3.46g}{3.47g}\times 1g=0.997g$ of oxygen will form.

Hence, the mass of oxygen per gram of sulfur for sulfur dioxide is 0.997 g

For B:

The chemical equation for decomposition of sulfur trioxide follows:

$2SO_3\rigtarrow 2S+3O_2$

We are given:

Mass of sulfur = 5.50 g

Mass of oxygen = 8.25 g

To calculate the mass of oxygen per gram of sulfur, we apply unitary method:

For every 5.50 g of sulfur, 8.25 g of oxygen will form.

So, for 1 gram of sulfur, $\frac{8.25g}{5.50g}\times 1g=1.5g$ of oxygen will form.

Hence, the mass of oxygen per gram of sulfur for sulfur trioxide is 1.5 g

3 0

3 years ago