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4 years ago

Find two consecutive integers whose sum is -7.

Mathematics

1 answer:

kaheart [24]4 years ago

4 0

-3 and -4
-4+(-3)=-7
Not much explaining to do, surprised you couldn't get this one

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PLZZZZZZZZ GET IT RIGHT PLZZ I AM GOING TO GIVE BRAINLEST TO THE PERSON WHO GETS IT RIGHT

White raven [17]

Answer:

D): -2.14 < |-2.8| < √10

Step-by-step explanation:

• Always a negative value is less than a positive value.

• |-2.8| = 2.8, but it is less than √10

• √10 = 3.162 which the greatest

$.$

3 0

3 years ago

Read 2 more answers

Which expression is equivalent to (5g^4+5g^3-17g^2+6g)-(3g^4+6g^3-7g^2-12)/g+2

ankoles [38]

Option C:

$2 g^{3}-5 g^{2}+6$

Solution:

Given expression:

$$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}$

To find which expression is equal to the given expression.

$$\frac{\left(5 g^{4}+5 g^{3}-17 g^{2}+6 g\right)-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right)}{g+2}$

Expand the term $-\left(3 g^{4}+6 g^{3}-7 g^{2}-12\right):-3 g^{4}-6 g^{3}+7 g^{2}+12$

$$=\frac{5 g^{4}+5 g^{3}-17 g^{2}+6 g- 3 g^{4}-6 g^{3}+7 g^{2}+12}{g+2}$

Arrange the like terms together.

$$=\frac{5 g^{4}- 3 g^{4}+5 g^{3}-6 g^{3}-17 g^{2}+7 g^{2}+6 g+12}{g+2}$

$$=\frac{2 g^{4}- g^{3}-10 g^{2}+6 g+12}{g+2}$

Factor the numerator $2 g^{4}-g^{3}-10 g^{2}+6 g+12=(g+2)\left(2 g^{3}-5 g^{2}+6\right)$

$$=\frac{(g+2)\left(2 g^{3}-5 g^{2}+6\right)}{g+2}$

Cancel the common factor g + 2, we get

$=2 g^{3}-5 g^{2}+6$

Hence option C is the correct answer.

8 0

3 years ago

Read 2 more answers

Draw 8 lines that are between 1inch and 3 inches long

Alex787 [66]

This is not something we can really help you with, you'll have to do on your own paper. Just get a ruler and draw 8 different lines that measure 1-3 inches.

5 0

3 years ago

In mathematics given that x=L2-L1/L1(O2-O1).

Assoli18 [71]

Answer:

1. L1 = $\frac{L2}{X(O2 -O1)}$

2. O2 = $\frac{L2 - L1(1 + XO1)}{XL1}$

Step-by-step explanation:

Given: x = $\frac{L2 - L1}{L1(O2 -O1)}$

1. To make L1 the subject of formula;

x = $\frac{L2 - L1}{L1(O2 -O1)}$

cross multiply to have;

L2 - L1 = xL1(O2 - O1)

collect like terms,

L2 = xL1(O2 - O1) + L1

factorize the right hand side;

L2 = L1[x(O2 - O1)]

L1 = $\frac{L2}{X(O2 -O1)}$

2. To make O2 the subject of formula;

x = $\frac{L2 - L1}{L1(O2 -O1)}$

cross multiply to have;

L2 - L1 = xL1(O2 - O1)

open the bracket to have;

L2 - L1 = xL1O2 - xL1O1

⇒ xL1O2 = L2 - L1 + xL1O1

O2 = $\frac{L2-L1 + XL1O1}{XL1}$

= $\frac{L2 - L1(1 + XO1)}{XL1}$

4 0

3 years ago

Compare decimals <,>,= (4.63) ○ (4.3)

vekshin1

4.63 > 4.3 because 4.63 > 4.30

4.3 = 4.30

5 0

3 years ago