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tamaranim1 [39]
3 years ago
9

Need Help PLLLEEAASSSSEEEE,

Mathematics
1 answer:
Licemer1 [7]3 years ago
7 0
(x-1)^2= 16(y-2)

(^2 is the exponent)
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Can you take a picture of your whole worksheet? only the front page

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3 years ago
PLEASE HELP ME WITH BOTH QUESTIONS<br> THANKS!!
vitfil [10]

First one:

cos(A)=AC/AB=3/4.24

cos(B)=BC/AB=3/4.24

Cos(A)/cos(B)=AC/AB / (BC/AB) = AC/AB * AB/BC = AC/BC=3/3=1


Second one:

To solve this problem, we have to ASSUME AFE is a straight line, i.e. angle EFB is 90 degrees. (this is not explicitly given).

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8 0
3 years ago
Find the area?<br> Show work
Ivenika [448]

Answer:

294 square units

Step-by-step explanation:

35^2-21^2=a^2

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Answer=294

4 0
3 years ago
What is the solution set of x2 + 5x + 1 = 0?
DerKrebs [107]

Answer:

\huge\boxed{\left\{-\dfrac{5+\sqrt{21}}{2};\ \dfrac{-5+\sqrt{21}}{2}\right\}}

Step-by-step explanation:

x^2+5x+1=0\\\\\text{Use the quadratic formula:}\\\\\text{For}\ ax^2+bx+c=0\\\\\Delta=b^2-4ac\\\\\text{if}\ \Delta < 0,\ \text{then the equation has no real solution}\\\text{if}\ \Delta=0,\ \text{then the equation has one real solution}\ x=\dfrac{-b}{2a}\\\text{if}\ \Delta>0,\ \text{then the equation has two real solution}\ x=\dfrac{-b\pm\sqrt{\Delta}}{2a}

\text{We have}\\\\a=1,\ b=5,\ c=1\\\\\Delta=5^2-4(1)(1)=25-4=21>0\\\\x=\dfrac{-5\pm\sqrt{21}}{2(1)}=\dfrac{-5\pm\sqrt{21}}{2}

3 0
3 years ago
Petes dog weighed 30 pounds it then lost 16% of it's weight how much did pete lose
Vlad [161]

Answer:

The dog lost 4.8 pounds! Goodluck!


Step-by-step explanation:


6 0
2 years ago
Read 2 more answers
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