Answer:
2Fe + 3O₂ → 2Fe₂O₃
Limiting reactant: O₂
2Fe + O₂ → 2FeO
Limiting reactant: Fe
Explanation:
2Fe + 3O₂ → 2Fe₂O₃
2Fe + O₂ → 2FeO
These are the possible reactions:
In first case, 2 moles of Fe need 3 mol of oyxgen to react
If I have 5 moles of Fe, I will need (5 .3)/2 = 7.5 moles of O₂
Then, the oxygen is my limiting ( I only have 4 moles)
3 moles of O₂ need 2 moles of Fe
If I have 4 moles of O₂, I will need (4 .2)/3 = 2.66 moles (I have 5)
Fe, is the reactant in excess.
For second case, 2 moles of Fe need 1 mol of O₂, to react.
If I have 5 moles of Fe, I will need ( 5 .1) / 2 =2.5 moles of O₂
I have 4 moles of oxygen, so now it is my excess.
1 mol of O₂ need 2 moles of Fe, to react
If I have 4 moles of O₂, I will need the double of amount, 8 moles of Fe.
I have 5 moles, then the Fe is my limtiing reactant.
