Answer:
The correct answer is 187.7 J/Jg.
Explanation:
The formula for finding the specific heat of fusion is,
Specific heat of fusion = Q/m
Here Q is the heat energy added, signified in kJ, and m is the mass of the object in kg.
Based on the given information, the heat energy added or Q is 869 kJ and the mass of the ice is 4.6 Kg
Now putting the values in the formula we get,
Specific heat of fusion = Q/m
Specific heat of fusion = 863 kJ / 4.6 Kg = 187.7 J/Kg
Answer:
1. 1568 J
2. 0 J
3. 1176 J
Explanation:
PE = mgh
(PE = Potential Energy) = (m = mass)(g = gravitational force which is 9.8)(h = height)
1. (3)(9.8)(20) = 1568 J
2. PE = (3)(9.8)(0) = 0 J
3. (5)(9.8)(24) = 1176 J
Answer:
The answer to your question is 25.9 g of KCl
Explanation:
Data
Grams of KCl = ?
Volume = 0.75 l
Molarity = 1 M
Formula
Solve for number of moles
Substitution
Number of moles = 1 x 0.75
Simplification
Number of moles = 0.75 moles
Molecular mass KCl = 39 + 35.5 = 34.5
Use proportions to find the grams of KCl
34.5 g of KCl ---------------- 1 mol
x ---------------- 0.75 moles
x = (0.75 x 34.5) / 1
x = 25.9 g of KCl
Answer:
The atomic nucleus is the small, dense region consisting of protons and neutrons at the center of an atom
