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2 years ago

The rate constant for a first-order reaction is 2.4 x 10-4 L/(mol's) at 600 K and 6.2 x 10-4L/(mol · s) at 900 K.

Chemistry

1 answer:

Alika [10]2 years ago

6 0

Answer:

(R = 8.31 J/(mol · K)) 0.88 × 104 J/mol 1.42 × 102 J/mol 1.42 × 104 J/mol at 600 K and 6.2 × 10-4 L/(mol · s) at 900 K. Calculate the activation energy.

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Calculate the percent error in the atomic weight if the mass of a Cu electrode increased by 0.4391 g and 6.238x10-3 moles of Cu

PIT_PIT [208]

Answer:

10.77%

Explanation:

Molar mass of Cu = mass deposited/number of moles of Cu

Molar mass of Cu = 0.4391 g/6.238x10^-3 moles

Molar mass of Cu = 70.391 g/mol

%error = 70.391 g/mol - 63.546 g/mol/63.546 g/mol × 100

%error = 10.77%

6 0

2 years ago

A strong compact cuticle makes for

steposvetlana [31]

Answer:

resistant hair

Explanation:

a strong compact cuticle makes for the resistance hair

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2 years ago

Bees help flowers reproduce through a process called __________. *

Ostrovityanka [42]

Answer:

Pollination

Explanation:

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3 years ago

How many grams of Ni are formed from 55.3 g of Ni2O3? 2Ni2O3(s)⟶4Ni(s)+3O2(g)

Neko [114]

Answer:

39.2 g

Explanation:

2Ni₂O₃(s) ⟶ 4Ni(s) + 3O₂(g)

First we convert 55.3 grams of Ni₂O₃ into moles of Ni₂O₃, using its molar mass:

55.3 g ÷ 165.39 g/mol = 0.334 mol Ni₂O₃

Then we convert 0.334 moles of Ni₂O₃ into moles of Ni, using the stoichiometric coefficients of the balanced reaction:

0.334 mol Ni₂O₃ * $\frac{4molNi}{2molNi_2O_3}$ = 0.668 mol Ni

Finally we calculate how much do 0.668 Ni moles weigh, using the molar mass of Ni :

0.668 mol Ni * 58.69 g/mol = 39.2 g

7 0

3 years ago

A tank holds 6.90 m3 of water. What is the volume in ft3? (3.28 ft = 1 m, Remember significant figures, but this answer does not

AleksAgata [21]

Volume of tank = $6.9 m^{3}$ (given)

Since, $1 m = 3.28 ft$

So,

$1 m^{3} = 35.287 ft^{3}$

For $6.9 m^{3}$ :

$6.9\times 35.287 ft^{3} = 243.4803 ft^{3}$

The significant rule for multiplication, states that the number of significant figures in the answer obtained by multiplication is determined by the value with the lowest number of significant digits.

Since, the minimum number of decimal places in the above multiplication operation is 1 so, the final result must be upto 1 decimal place only.

$243.4803 ft^{3} \simeq 243.5 ft^{3}$

Hence, volume in $ft^{3}$ is 243.5.

5 1

2 years ago

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