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fredd [130]
3 years ago
9

I need to check some chemistry questions. Help with any question is appreciated! :) Please include an explanation with your conc

lusion.

Chemistry
1 answer:
finlep [7]3 years ago
4 0

1. 4.67 kg; 2. 4.8 ×10^5 kg; 3. 0.106 cm^3; 4. 1.7 g/cm^3

<em>Q1. Mass of Hg </em>

Mass = 345 mL × (13.53 g/1 mL) = 4670 g = 4.67 kg

<em>Q2. Mass of Pb </em>

<em>Step 1</em>. Calculate the <em>volume of the Pb</em>.

<em>V = lwh</em> = 6.0 m × 3.5 m × 2.0 m = 42.0 m^3

<em>Step 2</em>. Calculate the <em>mass of the Pb</em>.

Mass = 42.0 m^3 × (11 340 kg/1 m^3) = 4.8 × 10^5 kg

<em>Q3. Volume of displaced water </em>

Volume of Ag = 0.987 g × (1 cm^3/9.320 g) = 0.106 cm^3

<em>Archimedes</em>: volume of displaced water = volume of Ag = <em>0.106 cm^3</em>

<em>4. Density of metal </em>

<em>Step 1</em>. Convert <em>ounces to grams </em>

Mass = 3.35 oz × (28.35 g/1 oz) = 94.97 g

<em>Step 2</em>. Calculate the <em>volume in cubic inches </em>

<em>V = lwh</em> = 3.0 in × 2.5 in × 0.45 in = 3.38 in^3

<em>Step 3</em>. Convert <em>cubic inches to cubic centimetres</em><em> </em>

<em>V</em> = 3.38 in^3 × (2.54 cm/1 in)^3 = 55.3 cm^3

<em>Step 4</em>. Calculate the <em>density</em>

ρ = <em>m</em>/<em>V</em> = (94.97 g/55.3 cm^3) = 1.7 g/cm^3 (magnesium?)

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Magnesium has three naturally occurring isotopes(Mg-24, Mg-25, and Mg-26). The atomic mass and natural abundance of Mg-24 are 23
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Answer:

The answer to your question is below

Explanation:

Data

               Atomic mass               Abundance

Mg -24 =    23.9850                         79%

Mg -25 =    24.9858                         10%  

Mg - 26=          ?                                  ?

Process

1.- Find the abundance of Mg-26

The sum of the abundance of the three isotopes equals 100%

         

 Abundance Mg-24 + Abundance-Mg-25 + Abundance-26 = 100

            79 + 10 + Abundance-26 = 100

            Abundance Mg-26 = 100 -89

           Abundance Mg-26 = 11%

2.- Find the atomic mass of Mg-26, the average atomic mass is 24.31 amu

Average atomic mass = (abundance)(atomic mass- 24) + (abundance)

                                         (atomic mass-25) + (abundance)(atomic mass-26)

    24.31 = (0.79)(23.9850)+ (0.10)(24.9858) + (Atomic mass-26)(0.11)

    24.31 = 18.94815 + 2.4986 + 0.11(atomic mass-26)

    24.31 = 21.4342 + 0.11(atomic mass- 26)

    0.11(atomic mass-26) = 24.31 - 21.4342

    0.11(atomic mass-26) = 2.8758

    Atomic mass-26 = 2.8758/0.11

 <u>   Atomic mass-26 = 26.1436 amu</u>

8 0
3 years ago
Read 2 more answers
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