Answer:
9.48
Step-by-step explanation:
Complete question
<em>A stainless steel patio heater is a square pyramid. The length of one side of the base is 89.6 The slant height of the pyramid 90.1. What is the height of the pyramid?</em>
To get the height of the pyramid, we will use pythagoras theorem.
slant height l is the hypotenuse
length of the base is the adjacent
height of the pyramid is the opposite
According to the theorem;
l² = h² + b²
90.1² = h² + 89.6²
8,118.01 = <em>h²+</em>8,028.16
h²= 8,118.01 - 8,028.16
h² = 89.85
h =√89.85
h = 9.48
Hence the height of the pyramid will be 9.48
<em>Note that the value of the slant height was assumed to solve the problem</em>.
(1) [6pts] Let R be the relation {(0, 1), (1, 1), (1, 2), (2, 0), (2, 2), (3, 0)} defined on the set {0, 1, 2, 3}. Find the foll
goldenfox [79]
Answer:
Following are the solution to the given points:
Step-by-step explanation:
In point 1:
The Reflexive closure:
Relationship R reflexive closure becomes achieved with both the addition(a,a) to R Therefore, (a,a) is 
Thus, the reflexive closure: 
In point 2:
The Symmetric closure:
R relation symmetrically closes by adding(b,a) to R for each (a,b) of R Therefore, here (b,a) is:

Thus, the Symmetrical closure:

To convert from rectangular to polar we will use these 2 formulas:
and
.
The r value found serves as the first coordinate in our polar coordinate, and the angle serves as the second coordinate of the pair. We are told to find 2. Since the r value will always be the same (it's the length of the hypotenuse created in the right triangle we form when determining our angle theta), the angle is what is going to be different in our coordinate pairs. We use the x and y coordinates from the given rectangular coordinate to solve for the r in both our coordinate pairs.
which gives us an r value of
. That's r for both coordinate pairs. Now we move to the angle. Setting up according to our formula we have
.
This asks the question "what angle(s) has/have a tangent of -1?". That's what we have to find out! Since the tangent ratio is y/x AND since it is negative, it is going to lie in a quadrant where x is negative and y is positive, AND where x is positive and y is negative. Those quadrants are 2 and 4. In QII, x is negative so the tangent ratio is negative here; in QIV, y is negative so the tangent ratio is negative here as well. Now, if we type inverse tangent of -1 into our calculators in degree mode, we get that the angle that has a tangent of -1 is -45. Measured from the positive x axis, -45 does in fact go into the fourth quadrant. However, since the inverse tangent of -1 is -45, we also have a 45 degree angle in the second quadrant. Those are reference angles, mind you. A 45 degree angle in QII has a coterminal angle of 135 degree; a 45 degree angle in QIV has a coterminal angle of 315. If you don't understand that, go back to your lesson on reference angles and coterminal angles to see what those are. So our polar coordinates for that rectangular coordinate are
and

0=6x^3+8
-8 -8
-8=6x^3
---- ------
6 6
(-8)/6=x^3
cube root each side to get
∛[(-8)/6]=x or F(x)=∛[(-8)/6]
F(x)=-1.100642...