Answer:
D (-9,3)
F (-5,-5)
Step-by-step explanation:
Since in the above case, the beaker has two sections each with different radius and height, we will divide this problem into two parts.
We will calculate the volume of both the beakers separately and then add them up together to get the volume of the beaker.
Given, π = 3.14
Beaker 1:
Radius (r₁) = 2 cm
Height (h₁) = 3 cm
Volume (V₁) = π r₁² h₁ = 3.14 x 2² x 3 = 37.68 cm³
Beaker 2:
Radius (r₂) = 6 cm
Height (h₂) = 4 cm
Volume (V₂) = π r₂² h₂ = 3.14 x 6² x 4 = 452.16 cm³
Volume of beaker = V₁ + V₂ = 37.68 + 452.16 = 489.84 cm³
Answer:
The graph of this piece-wise function is attached below.
Step-by-step explanation:
Given the function
- A piece-wise function is a function which has multiple pieces.
- Each of the pieces have their own restrictions.
- The domain of a function is the set of input, or x, values for which the function is defined.
- The range is the set of all values taken by the function
As the piece
has the domain [-5, 3) and graph of this piece is attached below.
and
has the domain [3, 7) and graph of this piece is attached below.
So, the domain of the piece-wise function can be composed as [-5, 3) U [3, 7) and range has the interval
.
i.e.
Domain: [-5, 3) U [3, 7)
Range: ![\:\left[-1,\:27\right]](https://tex.z-dn.net/?f=%5C%3A%5Cleft%5B-1%2C%5C%3A27%5Cright%5D)
The graph of this piece-wise function is attached below.
<em>Keywords: piece-wise function, domain, range</em>
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Hoi!
To solve this, first plug in the values for x and y.
x = 2, so anywhere you see x, put 2 in its place.
y = 3, so anywhere you see y, put 3 in its place.

4 × 2 = 8

× 3 =


=
is your answer.
Answer:
23, 26, 29
Step-by-step explanation:Skip count by 3