Answer:
the volume of 5.0 g CO2 is 2.6L
CO2 at tsp
It turns blue litmus into red .
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Answer:
ClO⁻(aq) + I⁻(aq) → Cl⁻(aq) + IO⁻(aq)
Explanation:
The reactions are:
(1) ClO⁻(aq) + H₂O(l) → HClO(aq) + OH⁻(aq) [fast]
(2) I⁻(aq) + HClO(aq) → HIO(aq) + Cl⁻(aq) [slow]
(3) OH⁻(aq) + HIO(aq) → H₂O(l) + IO⁻(aq) [fast]
By adding up the 3 equations we get:
ClO⁻(aq) + <em>H₂O(l)</em> + I⁻(aq) + <em>HClO(aq)</em> + <em>OH⁻(aq)</em> + <em>HIO(aq)</em> → <em>HClO(aq)</em> + <em>OH⁻(aq)</em> + <em>HIO(aq)</em> + Cl⁻(aq) + <em>H₂O(l)</em> + IO⁻(aq)
And by canceling common terms on both sides, we can get the overall equation:
ClO⁻(aq) + I⁻(aq) → Cl⁻(aq) + IO⁻(aq)
Therefore, the overall equation is ClO⁻(aq) + I⁻(aq) → Cl⁻(aq) + IO⁻(aq).
I hope it helps you!
I think the correct answer from the choices listed above is option C. It would be Cl2 (g) + 2Kl (s) = 2KCl (s) + l2 (g) that <span>describes a single-replacement reaction where Cl replaces I. Hope this answers the question. Have a nice day.</span>
Answer:
1Ag+2S⇔1Ag2S
Explanation:
The first step is to see how many of each element are on each side of the equation. There is one silver on the left and one silver on the right, so you can leave those alone. However, there is one sulfur on the left and two on the right. You cannot multiply the right by 2 because then that would upset the balance of the silver, but you can multiply the sulfur by 2. Therefore, the equation should be 1Ag+2S⇔1Ag2S. Hope this helps!