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3 years ago

15

Find the moles in 0.0023 of Co, at STP:

1 answer:

Alexus [3.1K]3 years ago

7 0

What is does that mean 0.0023 cooooo

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PLEASE HURRY! What is the relationship between distance and magnetic attraction? Give me some examples please. Pictures needed.

Sholpan [36]

Magnetism is inversely proportional to distance
this means that if distance increases magnetic attraction force decreases

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3 years ago

How many more times intense is an earthquake that measures 8 on the Richter scale than an earthquake that measures 5? Explain yo

djyliett [7]

The answer on edguinity is A magnitude 8 earthquake is 1,000 times more intense than a magnitude 5 earthquake. A magnitude 8 earthquake is 108 times more intense than a standard earthquake, while a magnitude 5 earthquake is 105 times more intense than a standard earthquake, and 108 ÷ 105 = 103. Each unit increase on the Richter scale corresponds to an intensity increase by a factor of 10. So from 5 to 8 on the Richter scale, the intensity increases by 103 = 1,000.

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3 years ago

Read 2 more answers

Groundwater in Pherric, New Mexico, initially contains 1.800 mg/L of iron as Fe3+. What must the pH be raised to in order to pre

xenn [34]

Answer : The pH will be, 3.2

Explanation :

As we known that the value of solubility constant of ferric hydroxide at $25^oC$ is, $2.79\times 10^{-39}$

Amount or solubility of iron consumed = (1.800 - 0.3) mg/L = 1.5 mg/L

The given solubility of iron convert from mg/L to mol/L.

$1.5mg/L=\frac{1.5\times 10^{-3}g/L}{56g/mol}=2.7\times 10^{-7}mol/L$

The chemical reaction will be:

$Fe(OH)_3\rightarrow Fe^{3+}+3OH^-$

The expression of solubility constant will be:

$K_{sp}=[Fe^{3+}]\times [3OH^-]^3$

Now put all the given values in this expression, we get the concentration of hydroxide ion.

$2.79\times 10^{-39}=(2.7\times 10^{-7})\times [3OH^-]^3$

$[OH^-]=1.5\times 10^{-11}M$

Now we have to calculate the pOH.

$pOH=-\log [OH^-]$

$pOH=-\log (1.5\times 10^{-11})$

$pOH=10.8$

Now we have to calculate the pH.

$pH+pOH=14\\\\pH=14-pOH\\\\pH=14-10.8\\\\pH=3.2$

Therefore, the pH will be, 3.2

4 0

3 years ago

Seawater is typically 3.5% salt and has a density of 1.03 g/mL. How many grams of salt would be needed to prepare enough seawate

Bas_tet [7]

Answer:

Amount of salt needed is around 2.3*10³ g

Explanation:

The salt content in sea water = 3.5 %

This implies that there is 3.5 g salt in 100 g sea water

Density of seawater = 1.03 g/ml

Volume of seawater = volume of tank = 62.5 L = 62500 ml

Therefore, the amount of seawater required is:

$=Density*Volume = 1.03g/ml*62500ml = 6.44*10^{4} g$

The amount of salt needed for the calculated amount of seawater is:

$=\frac{6.44*10^{4}g\ water*3.5g\ salt }{100g\ water} =2254 g =2.3*10^{3} g$

8 0

3 years ago

What is the difference between a strong base and a weak base?

slamgirl [31]

Answer:

A strong base produces more ions in solution than a weak base.

Explanation:

3 0

3 years ago