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maks197457 [2]
3 years ago
11

A fraction is written in simplest form when the GCF of the numerator and denominator is fill in the blank

Chemistry
1 answer:
Pachacha [2.7K]3 years ago
5 0
Is divided by the same number that goes into the number being divided evenly so there are no remainers

example....
2 2 1
__ ÷ __ = __
4 2 2
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How many grams of Cl2 must react to produce 0.0923 mol of AlCl3? Show work.
alexandr402 [8]

First, let's state the chemical reaction:

2Al+3Cl_2\to2AlCl_3\text{.}

We can find the number of moles of Cl2 required to produce 0.0923 moles of AlCl3, doing a rule of three: 3 moles of Cl2 reacted produces 2 moles of AlCl3:

\begin{gathered} 3molesCl_2\to2molesAlCl_3 \\ \text{?moles Cl}_2\to0.0923\text{ moles }AlCl_3\text{.} \end{gathered}

The calculation would be:

0.0923molesAlCl_3\cdot\frac{3molesCl_2}{2molesAlCl_3}=0.138molesCl_2.

And the final step is to convert this number of moles to grams. Remember that the molar mass can be calculated using the periodic table, so the molar mass of Cl2 is 70.8 g/mol, and the conversion is:

0.138molesCl_2\cdot\frac{70.8gCl_2}{1molCl_2}=9.770gCl_2.

The answer is that we need 9.770 grams of Cl2 to produce 0.0923 moles of AlCl3.

3 0
1 year ago
Mercury is often used as an expansion medium in a thermometer. The mercury sits in a bulb on the bottom of the thermometer and r
postnew [5]
Ok yeah a ha yeah wow it is 13.543 g/× compare that with e 13.5
3 0
3 years ago
What is the Ground state electron configuration for lead?
notsponge [240]

Answer:

Lead atoms have 82 electrons and the shell structure is 2.8. 18.32. 18.4.

Explanation:

The ground state electron configuration of ground state gaseous neutral lead is [Xe].

3 0
4 years ago
A bottle of concentrated aqueous sulfuric acid, labeled 98.0 wt% h2so4, has a concentration of 18.0 m. (a) how many milliliters
nadya68 [22]
<span>n this order, Ď=1.8gmL, cm=0.5, and mole fraction = 0.9 First, let's start with wt%, which is the symbol for weight percent. 98wt% means that for every 100g of solution, 98g represent sulphuric acid, H2SO4. We know that 1dm3=1L, so H2SO4's molarity is C=nV=18.0moles1.0L=18M In order to determine sulphuric acid solution's density, we need to find its mass; H2SO4's molar mass is 98.0gmol, so 18.0moles1Lâ‹…98.0g1mole=1764g1L Since we've determined that we have 1764g of H2SO4 in 1L, we'll use the wt% to determine the mass of the solution 98.0wt%=98g.H2SO4100.0g.solution=1764gmasssolution→ masssolution=1764gâ‹…100.0g98g=1800g Therefore, 1L of 98wt% H2SO4 solution will have a density of Ď=mV=1800g1.0â‹…103mL=1.8gmL H2SO4's molality, which is defined as the number of moles of solute divided by the mass in kg of the solvent; assuming the solvent is water, this will turn out to be cm=nH2SO4masssolvent=18moles(1800â’1764)â‹…10â’3kg=0.5m Since mole fraction is defined as the number of moles of one substance divided by the total number of moles in the solution, and knowing the water's molar mass is 18gmol, we could determine that 100g.solutionâ‹…98g100gâ‹…1mole98g=1 mole H2SO4 100g.solutionâ‹…(100â’98)g100gâ‹…1mole18g=0.11 moles H2O So, H2SO4's mole fraction is molefractionH2SO4=11+0.11=0.9</span>
5 0
3 years ago
Pls hurry I need to have this ASAP
tankabanditka [31]

Answer:

The image is too blurry to see anything

Explanation:

Please upload a better image

3 0
2 years ago
Read 2 more answers
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