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2 years ago

Aluminum has a specific heat of 897 j/kg c. methanol has a specific heat of 2450 j/kg c.

Chemistry

1 answer:

Vikki [24]2 years ago

7 0

Answer:

$\sf \: correct \: answer \: would \: be \: methanol!$

Explanation:

Specific Heat: The specific Heat of any material is the heat absorbed or evolved by the material to raise or fall it's temperature by 1°C per unit mass of the material.

The heat absorbed or evolved (Q) is directly proportional to the mass of substance(m) and rise or fall of temp(∆T)

The general formula for specific heat is,

$\sf \: \: \: \: \: s = \frac{Q}{m\Delta T}$

Where

s is specific heat,
Q is the Heat absorbed or evolved
m is mass of substance
& ∆T is change is temperature

Now coming to your question,

The specific heat of Aluminium is 897 J/kg °C

The specific heat of Aluminium is 897 J/kg °C& specific heat of methanol is 2450 J/kg ° C

The definition states that, if the specific heat would be more, more amount of heat will be required for per unit change in temperature.

The specific heat of Aluminium is 897 J/kg °C which means for one kilogram aluminium, 897 Joule energy is required to change it's temperature by 1°C & Similarly for one kilogram methanol 2450 joule energy is required.

Hence, the correct answer would be methanol!

learn more about specific heat here,

brainly.com/question/27365354

brainly.com/question/27598037

$\small \sf \: Thanks \: for \: joining \: brainly \: community!$

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3 years ago

An Erlenmeyer flask containing 20.0 mL of sulfuric acid of an unknown concentration was titrated with exactly 15.0 mL of 0.25 M

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Answer:

0.09375M

Explanation:

There are two methods of going about this, either we use dilution formula (easiest and fastest) or we solve through molarity.

Using dilution formula,

C2 (H2SO4) = ?

C1 (NaOH) = 0.25M

V2 (H2SO4) = 20cm³

V1 (NaOH) = 15cm³

However we can solve using molarity method

Equation of reaction =

2NaOH + H2SO4 ====》 Na2SO4 + 2H2O

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X moles = 15cm³

X = (0.25 * 15) / 1000

X = 0.00375 moles is present in 15cm³ of NaOH

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2 moles of NaOH requires 1 mole of H2SO4

Therefore

0.00375 / 2 = 0.001875 moles is present in H2SO4

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Answer:

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Explanation:

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