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AleksandrR [38]
4 years ago
12

A ______________ is a prediction of an outcome and the basis for experimentation.

Chemistry
2 answers:
a_sh-v [17]4 years ago
7 0
A hypothesis is a prediction of an outcome and the basis for experimentation. 
erica [24]4 years ago
6 0

Answer: Hypothesis

Explanation:

A hypothesis is a proposed explanation for the experiment. Hypothesis can be scientific only when scientific method is used to prove the hypothesis.

Scientific hypothesis is generally based on the previous observations that cannot be explained satisfactorily with the available scientific theories that are present already.

It is mostly a prediction of result which is based on the experiment.

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The rock in a particular iron ore deposit contains 82 % Fe2O3 by mass. How many kilograms of the rock must be processed to obtai
Zinaida [17]

Answer:

Mass of rock = 4533.4 kg

Explanation:

Percent composition is percentage by the mass of element present in the compound.

Given that the Fe_2O_3 is 82 % by mass.

It means that 82 kg of Fe_2O_3 is present in 100 kg of rock

To find the mass of rock which contains 2600 kg of iron

2600 kg = 2600*1000 g

2 moles of iron are present in 1 mole of Fe_2O_3

Molar mass of iron = 55.845 g/mol

Mass of 2 moles = 55.845 * 2 = 111.69 g/mol

Molar mass of Fe_2O_3 = 159.69 g/mol

It means,

111.69 g of iron are present in 159.69 g of Fe_2O_3

1 g of iron is present in 159.69/111.69 g of Fe_2O_3

2600*1000 g is present in (159.69/111.69)*2600*1000 g of Fe_2O_3

Mass of  Fe_2O_3 = 3717378.47 g =3717.38 kg

Thus,

82 kg of Fe_2O_3 is present in 100 kg of rock

1 kg of Fe_2O_3 is present in 100/82 kg of rock

3717.38 kg of Fe_2O_3 is present in (100/82)*3717.38 kg of rock

Mass of rock = 4533.4 kg

5 0
3 years ago
Read 2 more answers
Determine the energy of the electron in the 1s orbital of a helium ion (He+ )
Luda [366]
He Rydberg formula can be extended for use with any hydrogen-like chemical elements. 
<span>1/ λ = R*Z^2 [ 1/n1^2 - 1/n2^2] </span>
<span>where </span>
<span>λ is the wavelength of the light emitted in vacuum; </span>
<span>R is the Rydberg constant for this element; R 1.09737x 10^7 m-1 </span>
<span>Z is the atomic number, for He, Z =2; </span>
<span>n1 and n2 are integers such that n1 < n2 </span>
<span>The energy of a He+ 1s orbital is the opposite to the energy needed to ionize the electron that is </span>
<span>taking it from n = 1 (1/n1^2 =1) to n2 = ∞ (1/n2^2 = 0) </span>
<span>.: 1/ λ = R*Z^2 = 1.09737x 10^7*(2)^2 </span>
<span>λ = 2.278*10^-8 m </span>
<span>E = h*c/λ </span>
<span>Planck constant h = 6.626x10^-34 J s </span>
<span>c = speed of light = 2.998 x 10^8 m s-1 </span>
<span>E = (6.626x10^-34*2.998 x 10^8)/(2.278*10^-8) = 8.72*10^-18 J ion-1 </span>
<span>Can convert this value to kJ mol-1: </span>
<span>(8.72*10^-18*6.022 x 10^23)/1*10^3 = 5251 kJ mol-1 </span>
<span>Lit value: RP’s secret book: 5240.4 kJ mol-1 (difference is due to a small change in R going from H to He+) </span>
<span>So energy of the 1s e- in He+ = -5251 kJ mol-1</span>
6 0
3 years ago
#12, how do I solve this
Likurg_2 [28]
Find the molar mass of the compound, then get the unit cancel out until u reach "g"

5 0
3 years ago
Help help help help help help
MAXImum [283]
I did this in school and you should search the title in google and it will appear that what I did and it worked good luck
8 0
4 years ago
A chemical reaction has a ΔH of -2764 Kj. This indicates that the chemical reaction that took place was
ZanzabumX [31]

Exothermic

Explanation:

A chemical reaction that has ΔH of -2764Kj indicates that the reaction that took place was an exothermic reaction.

  • The enthalpy changes accompanying a reaction causes heat changes.
  • In an exothermic reaction, heat is usually liberated to the surroundings.
  • The environment becomes hotter at the end of the reaction.
  • It is assigned a negative value because the sum of the heat contents of products is less than that of reactants.
  • A positive sign is for an endothermic reaction.

learn more:

Exothermic reactions brainly.com/question/10567109

#learnwithBrainly

4 0
3 years ago
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