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STatiana [176]
3 years ago
15

16

Physics
2 answers:
frozen [14]3 years ago
7 0

Answer:

so you should try to find what things would cause the most risk. apply these to yourself as if you were doing this project and then think which two ways you can stay safe.

Explanation:

krek1111 [17]3 years ago
6 0

Explanation:

the table and the wooden block

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Name several ways science impacts society.
Nataliya [291]
asthetics, education, healthier life, make life easier, find cures and treatments
3 0
3 years ago
If 500g of water at 20 degrees C is mixed with 750g of water at 30 degrees C, what will the temperature of the mixture be?
hjlf

Answer:

26 ^\circ C

Explanation:

Given that the temperature of  500g of water and 750 g of water are

at 20^{\circ}C and 30^\circ C respectively.

Let m_1=500g, T_1= 20^\circ C

and m_2=750g, T_2= 30^\circC.

The specific heat capacity of water is,

C= 4.186 J/g ^\circ C.

Let the final temperature of the mixture be T^\circ C.

As there is no energy loss, so, the energy loss by the water at higher temperature, i.e. 30^\circ C, will be equal to the energy gain by the water at lower temperature, i.e. 20^{\circ}C.

m_2C (T_2-T)=m_1C(T-T_1)

\Rightarrow m_2 (T_2-T)=m_1(T-T_1) [ both sides divided by C ]

\Rightarrow m_2T_2-m_2T=m_1T-m_1T_1

\Rightarrow m_1T+m_2T=m_1T_1+m_2T_2

\Rightarrow T=\frac{m_1T_1+m_2T_2}{m_1+m_2}

Now, putting the given value in the above equation, we have

\Rightarrow T=\frac {500\times 20+750\times 30}{500+750}

\Rightarrow T=26^\circ C.

Hence, the temperature of the mixture will be 26 ^\circ C.

5 0
3 years ago
A certain airplane has a speed of 290.0 km/h and is diving at an angle of 0 : 30.0" below the horizontal when the pilot releases
prisoha [69]

Answer:

10.03 s is the time the decoy is in the air

Explanation:

From the information given we know:

  • \theta_{0}=-30 because is measured clockwise from horizontal.
  • The initial speed of the decoy is the plane's speed at the moment of release v_{0}=290 \:\frac{km}{h}

We will need to work in meters and m/s, so 290 \:\frac{km}{h} \cdot \frac{1000 \:m}{km} \cdot \frac{1\:h}{3600\:s} = 80.56 \:\frac{m}{s}

The horizontal motion of a projectile is given by:

x-x_{0}=v_{0x}\cdot t

because v_{0x}=v_0cos(\theta_{0}), this becomes

x-x_{0}=(v_0cos(\theta_{0}))\cdot t

We have that \Delta x= 700\:m, solving for <em>t, </em>we have

t=\frac{\Delta x}{v_{0}cos\theta_{0}} \\t=\frac{700 \:m}{(80.56 \:\frac{m}{s} )\cdot cos(-30)} \\t= 10.03 \:s

5 0
3 years ago
A roller coaster is stationary at the top of a ramp.
Serjik [45]

Answer:

A

Explanation:

The roller coaster is stationary so the kinetic energy would be zero, but it is at the top of ramp so the potential energy would be high as its gravitational  so it would have to be A

6 0
3 years ago
A car goes 122m at 30m/s How long did it travel?
stellarik [79]

<u>Answer:</u>

It took \bf 4.07 \space\ \mathrm{s} to travel.

<u>Explanation:</u>

To calculate the time taken to travel a distance of 122 m at a speed of 30 m/s, we can use the formula for speed:

\boxed{speed = \frac{distance}{time}}.

We can substitute the known values, and then solve for time:

30 = \frac{122}{\mathrm {time}}

⇒ \mathrm{time } = \frac{122}{30}

⇒ \mathrm{time } \approx \bf 4.07 \space\ \mathrm{s}

3 0
1 year ago
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