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IgorC [24]
3 years ago
14

A ball is falling from the second floor balcony to the floor below

Physics
2 answers:
aleksandrvk [35]3 years ago
7 0

Answer:

KE increases and PE decreases

Explanation:

eimsori [14]3 years ago
5 0
KE increase and PE decreases
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75 pts!
jasenka [17]

again CORRECT ans is 4) light strikes the grooves → different wavelengths of light bend at different angles → diffracted wavelengths reach the eyes → the eyes see different colors.

moderator - plz review the ans as u deleted my right ans n approved the wrong ans :(

6 0
3 years ago
Read 2 more answers
If the distance between two charges is doubled, by what factor is the magnitude of the electric force changed? F_e final/F_e, in
motikmotik

To solve this problem we will apply the concepts related to Coulomb's law for which the Electrostatic Force is defined as,

F_{initial} = \frac{kq_1q_2}{r^2}

Here,

k = Coulomb's constant

q_{1,2} = Charge at each object

r = Distance between them

As the distance is doubled so,

F_{final} = \frac{kq_1q_2}{( 2r )^2}

F_{final} = \frac{ kq_1q_2}{ 4r^2}

F_{final} = \frac{1}{4} \frac{ kq_1q_2}{r^2}

F_{final} = \frac{1}{4} F_{initial}

\frac{F_{final}}{ F_{initial}} = \frac{1}{4}

Therefore the factor is 1/4

6 0
3 years ago
At the 1 s mark, which objects have equal momentum?
Rudik [331]
C. The bowling ball and the bicycle

p = mv
P of bike = 12x5 = 60
P of rock = 2x20 = 40
P of ball = 5 x 10 = 60
3 0
3 years ago
When a board with a box on it is slowly tilted to a larger and larger angle, common experience shows that the box will at some p
Savatey [412]

Answer:

c. The coefficient of kinetic friction is less than the coefficient of static friction

Explanation:

When the box finally does break loose. Then the component of the box weight which is parallel to the board weight parallel component, is equal to the \mu_gn.

w_{box}=\mu_gn

For the box to acce;erate thee must be non-zero net force acting on the box parallel to the board. Or we can say,

w_1>f_g\\w_1>\mu_gn

Therefore the force of kinetic friction must be less than the force of static friction. Thus,

\mu_g

3 0
3 years ago
The inductance in the drawing has a value of L = 9.4 mH. What is the resonant frequency f0 of this circuit?
yuradex [85]

Answer:

The resonant frequency of this circuit is 1190.91 Hz.

Explanation:

Given that,

Inductance, L=9.4\ mH=9.4\times 10^{-3}\ H

Resistance, R = 150 ohms

Capacitance, C=1.9\ \mu F=1.9\times 10^{-6}\ C

At resonance, the capacitive reactance is equal to the inductive reactance such that,

X_C=X_L    

2\pi f_o L=\dfrac{1}{2\pi f_oC}

f is the resonant frequency of this circuit  

f_o=\dfrac{1}{2\pi \sqrt{LC}}

f_o=\dfrac{1}{2\pi \sqrt{9.4\times 10^{-3}\times 1.9\times 10^{-6}}}

f_o=1190.91\ Hz

So, the resonant frequency of this circuit is 1190.91 Hz. Hence, this is the required solution.

4 0
3 years ago
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