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nika2105 [10]
3 years ago
9

2. A driver brings a car traveling at 22 m/s to a stop in 2.0 seconds. What is the car's acceleration?

Physics
2 answers:
Ad libitum [116K]3 years ago
8 0

Answer: a= m/s divide by sec

22m/s divided by 2.0sec

11m/s

Explanation: dividing the meter per second [m/s] by the second [s

sveta [45]3 years ago
5 0

Answer:

11 m/s²

Explanation:

Acc = v/t

Acc = 22 / 2.0

Acc = 11 m/s²

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What is the magnitude of g at a height above Earth's surface where free-fall acceleration equals 6.5m/s^2?
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The "magnitude of gravity" is described in terms of the acceleration
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4 0
3 years ago
‏A 50 - N x m torque acts on a wheel with a moment of inertia 150 kg x m² . If the wheel starts from rest , how long will it tak
denis-greek [22]

Answer:

t = 6.17 s

Explanation:

For a 1 revolution movement, \triangle \theta = 2\pi

Torque, \tau = 50 Nm

Moment of Inertia, I = 150 kg m^2

If the wheel starts from rest, w_{0} = 0 rad/s

The angular displacement of the wheel can be given by the formula:

\triangle \theta = \omega_0 t + 0.5 \alpha t^2................(1)

Where \alpha is the angular acceleration

\tau = I \alpha\\\alpha = \frac{\tau}{I} \\\alpha = 50/150\\\alpha = 0.33 rad/s^2

To get t, put all necessary parameters into equation (1)

2\pi = 0(t) + 0.5(0.33)t^2\\2\pi =0.5(0.33)t^2\\t^2 = \frac{4 \pi}{0.33} \\t^2 = 38.08\\t = 6.17 s

3 0
3 years ago
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