The solution is the mixture of the solute into the solvent particles. In 60 mL solution, 59.8 mL of solvent is added.
<h3>What are solute and solvent?</h3>
Solute and solvent are the components of a solution. They react and mix together to produce a homogenous mixture. The solute is a substance that is added to the solvent.
Solvents are substances that dissolve the added solute in them to make a homogenous solution.
Given,
Volume of Solute = 0.20 mL
Volume of Solution = 60 mL
The volume of solvent is calculated as:
Volume of solvent = Volume of solution - Volume of solute
= 60- 0.20
= 59.8 mL.
Therefore, 59.8 mL of solvent is present in 60 mL of solution.
Learn more about solute and solvent here:
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Yes because mechanical energy is the motion of an object. hope that helped!
Answer:
8.73
Explanation:
The concentration of acetic acid can be determined as follows:






Moles of
= 
=0.0090 moles
Moles of 
= 0.0090 moles
The equation for the reaction can be expressed as :
----->

Concentration of
ion = 
= 
= 0.052 M
Hydrolysis of
ion:
----->


⇒ 
= 
As K is so less, then x appears to be a very infinitesimal small number
0.052-x ≅ x





![[OH] = x =0.535*10^{-5}](https://tex.z-dn.net/?f=%5BOH%5D%20%3D%20x%20%3D0.535%2A10%5E%7B-5%7D)
![pOH = -log[OH^-]](https://tex.z-dn.net/?f=pOH%20%3D%20-log%5BOH%5E-%5D)
![pOH = -log[0.535*10^{-5}]](https://tex.z-dn.net/?f=pOH%20%3D%20-log%5B0.535%2A10%5E%7B-5%7D%5D)

pH = 14 - pOH
pH = 14 - 5.27
pH = 8.73
Hence, the pH of the titration mixture = 8.73
Answer: 
Explanation:
The balanced chemical reaction is,

The expression for Gibbs free energy change is,
![\Delta G_{rxn}=\sum [n\times \Delta G_(product)]-\sum [n\times \Delta G_(reactant)]](https://tex.z-dn.net/?f=%5CDelta%20G_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20G_%28product%29%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20G_%28reactant%29%5D)
![\Delta G_{rxn}=[(n_{CO_2}\times \Delta G_{CO_2})+(n_{CaO}\times \Delta G_{CaO})]-[(n_{CaCO_3}\times \Delta G_{CaCO_3})]](https://tex.z-dn.net/?f=%5CDelta%20G_%7Brxn%7D%3D%5B%28n_%7BCO_2%7D%5Ctimes%20%5CDelta%20G_%7BCO_2%7D%29%2B%28n_%7BCaO%7D%5Ctimes%20%5CDelta%20G_%7BCaO%7D%29%5D-%5B%28n_%7BCaCO_3%7D%5Ctimes%20%5CDelta%20G_%7BCaCO_3%7D%29%5D)
where,
n = number of moles
Now put all the given values in this expression, we get
![\Delta G_{rxn}=[(1\times -394.4)+(1\times -604.17)]-[(1\times -1128.76)]](https://tex.z-dn.net/?f=%5CDelta%20G_%7Brxn%7D%3D%5B%281%5Ctimes%20-394.4%29%2B%281%5Ctimes%20-604.17%29%5D-%5B%281%5Ctimes%20-1128.76%29%5D)

Therefore, the gibbs free energy for this reaction is, +130.19 kJ
Answer:
Carbon fiber if I'm correct