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4 years ago

9

Product A is an 8 oz. bottle of cough medication that sells for $1.36. Product B is a 16 oz. bottle of cough medication that cos

ts $3.20. Which product has the lower unit price?

1 answer:

11111nata11111 [884]4 years ago

8 0

Product A is 17 cents per oz.
Product B is 20 cents per oz.

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Can anyone please help me with these sums? I need it fast......Please give correct answers only. I will give brainliest.

soldier1979 [14.2K]

Answer:

rise/run= -20/5= -4/1=-4 slope

or you sound use the slope formula (y2-y1)/(x2-x1)

(-9-11)/(1+4)

-20/5

-4

Step-by-step explanation:

3 0

3 years ago

A toy rocket is launched vertically from 5 feet above ground level with an initial velocity of 112 feet per second. The height h

Masja [62]

Answer:

Step-by-step explanation:

a)The height h after t seconds is given by the equation h(t)=-16t^2+112t+5.

Where 5 represents 5feet above the ground and this is the height from which the rocket was launched.

The equation is a quadratic equation. The plot of this equation on a graph would give a parabola whose vertex would be equal to the maximum height travelled by the rocket.

The vertex of the parabola is calculated as follows,

Vertex = -b/2a

From the equation,

a = -16

b = 112

Vertex = - - 112/32= 3.5

So the rocket will attain maximum height at 3.5 seconds.

It will also take 3.5 seconds to reach the ground. This means it will take a total of 3.5 seconds + 3.5 seconds

= 7 seconds to hit the ground.

b) to find time it will take to be 100 feet above the ground,

-16t^2+112t-95 = 0

Using general quadratic equation formula,

a = -16

b = 112

c = -95

t = [-b+/-√b^2-4ac]/2a

t = [ -112 +/-√112^2-4×-16×-95]/16 × -2

= [-112 +/-√12544-6080]/-32

= (-112+80.4)/-32 or (-112-80.4)/-32

t = 0.9875 or t = 6.0125

So it will take 0.9875 or approximately 1 second to be 100 feet above the ground

7 0

3 years ago

A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-‐

cricket20 [7]

Answer:

<u>The final curse load of the local gym instructor is this:</u>

<u>High-‐impact aerobics = 1</u>

<u>Low-‐impact aerobics = 4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-‐impact aerobics, 64 wanted low-‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-‐impact aerobics = 8/14.25 = 0.5614

Low-‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-‐impact aerobics = 0

Low-‐impact aerobics = 4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-‐impact aerobics with .5614.

<u>The final course load is this:</u>

<u>High-‐impact aerobics = 1</u>

<u>Low-‐impact aerobics = 4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

7 0

3 years ago

Triangle A B C is shown. Angle A C B is a right angle. An altitude is drawn from point C to a point on side A B to form a right

mars1129 [50]

Answer:

$BC=15\ units$

Step-by-step explanation:

see the attached figure to better understand the problem

In the right triangle ABC

Applying the Pythagorean Theorem

$AB^2=AC^2+BC^2$

substitute the given values

$17^2=8^2+BC^2$

solve for BC

$BC^2=17^2-8^2$

$BC^2=225$

$BC=15\ units$

5 0

3 years ago

Read 2 more answers

PLEASE HELP! A) 6,135º C B) 6,681º C C) 502º C D) 47º C

Arada [10]

Answer: 47°C

Step-by-step explanation:

Since we are given the velocity, all we have to do is plug in 358 for v and solve for t.

$358=20\sqrt{273+t}$ [divide both sides by 20]

$17.9=\sqrt{273+t}$ [square both sides to cancel out square root]

$320.41=273+t$ [subtract both sides by 273]

$t=47.41$

Now that we know the temperature is 47.41°C, we know our answer choice is D.

8 0

3 years ago