Top right I’m pretty sure
Answer:
If the p-value is less than a given significance level, you reject the null hypothesis and accept the alternative hypothesis.
Step-by-step explanation:
Suppose you have a business in which you'd like to make a change to increase your business. After making the change, you can use a significance test it. To conduct a significance test, you make a null hypothesis which states essentially that no effect happened. You also make an alternative hypothesis that states the change had an effect. You then test the two to see which one stands. In a significance test, using the p-value from your sample you compare it to the null and alternative hypotheses. You make a conclusion when:
- If the p-value is less than a given significance level, you reject the null hypothesis and accept the alternative hypothesis since the evidence is in favor of it.
If the p-value is greater than the significance level, then you fail to reject the null hypothesis and cannot conclude. There isn't evidence in favor of the alternative hypothesis.
9514 1404 393
Answer:
72
Step-by-step explanation:
The triangles are said to be similar. (ΔNPQ ~ ΔRSQ) That means corresponding sides have the same ratio:
NP/RS = NQ/RQ = PQ/SQ = 24/32 = 21/28 = 3/4
This ratio, or scale factor, also applies to the perimeters of the two triangles.
perimeter NPQ / perimeter RSQ = 3/4
Using the given expressions for the perimeters, we have ...
(7x +2)/(10x -4) = 3/4
We can solve this equation in the usual way to find the value of x. Then we can use that value to find the perimeter of ΔNPQ.
4(7x +2) = 3(10x -4) . . . . . multiply both sides by 4(10x -4)
28x +8 = 30x -12 . . . . . eliminate parentheses
20 = 2x . . . . . . . . . . . add 12-28x to both sides
10 = x . . . . . . . . . . . divide both sides by 10
The perimeter of ΔNPQ is ...
7x +2 = 7(10) +2 = 72
The perimeter of triangle NPQ is 72 units.
Hello !
Here are some rules for logarithms : log ₐ b = n ⇔ aⁿ = b
log ₐ aⁿ = n
log ₐ (b·c) = logₐ b + log ₐ c
log ₐ bⁿ = n· log ₐ b ____________________________________________________
25=5²
625=5⁴
100 = 5² · 2²
____________________________________________________
(log₅ 25 + log₅ 625) / log₅100 =
(log₅ 5²+ log₅ 5⁴) / log₅ (5² · 2²) =
(log₅ 5²+ log₅ 5⁴) /( log₅ 5² + log₅ 2²) =
(2 + 4)/(2+log₅ 2² ) =
6/ (2+2·log₅2)=
6/2 + 6/ (2·log₅2) =
3+ 3/log₅2
log₅2 = 0.5
So 3+ 3/log₅2 = 3 + 3/0.5 =3 + 6 = 9
Answer : 9
Y = m + 3
you have to count the ones in between and add the 3 to fill in for b
