The distance formula:d = v i · t + a · t² / 2Sir G.: ( v i = 0 )
d G = 0 + 0.3 · t² / 2Sir A. : d A = 0 + 0.2 t² / 288 m = 0.3 t² / 2 + 0.2 t² / 2 / · 2 ( multiple both sides by 2 )176 = 0.3 t² + 0.2 t²176 = 0.5 t²t² = 176 : 0.5t² = 352t = √352t = 18.76 sd G. = 0.3 · 18.76² / 2 = 0.3 · 352 / 2 = 52.8 mAnswer: The knights collide at 52.8 m relative to Sir George`s starting point.
Answer:
i just took this test no joke and i got the correct answer which was c
Explanation:
the answer is waning Gibbous
The Waning Gibbous is an intermediary Moon phase. It starts right after the Full Moon, and it lasts until the Third Quarter.
Answer:
Potential difference is the work done in moving a positive test charge from infinity to the point in question.
Voltage is an expression of PD. (Joules / Coulomb)
Say that a capacitor has a PD of 5 Volts. The work in moving a positive test charge from the positive plate to the negative plate is -5 Joules/Coulomb or -5 volt. (At the positive plate the positive test charge (1 Coulomb) already has a PD of + 5 Volts.)
Answer:
d. the force is reduced by one quarter to 3.6 n
Explanation:
