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guapka [62]
2 years ago
11

A vehicle's mass is 1990kg. It is traveling at a speed of 28.0m/s. Determine the kinetic engine of the vehicle

Physics
1 answer:
irga5000 [103]2 years ago
8 0

Answer:      780080

Explanation: BY FORMULA OF K.E

                           K.E=  1/2 MV^2

                                 =  1/2 (1990)(28)^2

                                 =   780080 JOULE

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The level of mercury falls in a barometer<br>while taking it to a mountain.​
Alexxandr [17]

Answer:

This is due to a relative decrease in atmospheric pressure in high places.

Explanation:

Given that atmospheric pressure decreases at the higher point or ground, this reduced atmospheric pressure, however, will be unable to contain the Mercury in the barometer tube.

Therefore, at the top of the mountain where the air pressure is low, the barometer reading ultimately goes down.

Hence, the level of mercury falls in a barometer while taking it to a mountain "due to a relative decrease in atmospheric pressure in high places."

8 0
3 years ago
A cyclist travels 36km in 3 hours. What is the cyclist’s average speed?
dybincka [34]
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Assuming that this is the average rate the cyclist is moving at it would be 12 km/hr.
4 0
3 years ago
A block is balanced on top of a frictionless sphere of radius R. When the block is given a slight nudge it starts to slide down
Nataly_w [17]

Answer:\frac{R}{3}

Explanation:

Given

Sphere of Radius R

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mg\sin \theta -N=\frac{mv^2}{R}  , where v is velocity of block at any angle \theta

When block is just about to leave then N=0

therefore

mg\sin \theta =\frac{mv^2}{R}

v^2=gR\sin \theta-------------------1

Also by conserving Energy we get

Potential Energy=kinetic Energy of block

mgh=\frac{mv^2}{2}

here h=vertical distance traveled by block

From diagram

h=R-R\sin \theta

h=R(1-\sin \theta )

mgR(1-\sin \theta )=\frac{mv^2}{2}

2gR(1-\sin \theta )=v^2-----------------2

From 1 and  2

2(1-\sin \theta )=\sin \theta

3\sin \theta =2

\sin \theta =\frac{2}{3}

Thus from this value of h is

h=R(1-\sin \theta )

h=R(1-\frac{2}{3})

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3 0
4 years ago
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Lerok [7]

Answer:

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Thus, if we start with A grams of a given radioactive isotope, after a 1 half-life, we will have A/2 grams of the radioactive isotope.

In this case, we know that the sample has 110g of a radioactive isotope.

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110g/2 = 55g

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The answer that is closer to this result is option d (50 g), so that is the correct one.

5 0
3 years ago
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