Question

Please help asap!! binomial factor

Answer 1

Answer:

3x - 8

Step-by-step explanation:

the factors of the following equation $9x^{2} - 64 =$ are:

$(3x - 8)(3x + 8)$

If you look the equation you can notice that you don´t have a term like -48x or 48x, so the factors must have a positive and negative sign.  

Remember first you need to multiply each segment and finally add.

$(3x - 8)(3x + 8) = 9x^{2} - 24x + 24x -64$ = $9x^{2} - 64 =$

Answer 2

Answer:

The binomial factor of the given equation is 3x-8

Solution:

We know that,

$9=3\times3=3^{2}$

$64=8\times8=8^{2}$

According to the formula, $a^{2}b^{2} = (ab)^{2}$

we get, $9x^{2}-64=3^{2}x^{2}-8^{2}=(3x)^{2}-8^{2}$

From the formula, $a^{2}-b^{2} = (a+b) (a-b)$

Here in this step we can consider a as 3x and b as 8

On substituting the values we can simplify the above equation as, $9x^{2}-64 = (3x+8) (3x-8)$

The factors $9x^{2}-64$ are $(3x+8) and (3x-8)$

So, the answer is (3x-8)