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Oksi-84 [34.3K]
3 years ago
8

What is the product in simplest form state any restrictions on the variable x^2+7x+10/x+3?

Mathematics
2 answers:
almond37 [142]3 years ago
6 0

The expression given to us is:

\frac{x^2+7x+10}{x+3}

This can be rewritten as:

\frac{x^2+2x+5x+10}{x+3}

Now, let us take x as the common factor in the first two terms in the numerator and 5 as the common factor in the last two terms in the numerator. Thus, we get:

\frac{x^2+2x+5x+10}{x+3}=\frac{x(x+2)+5(x+2)}{x+3}

Now, taking (x+2) as the common factor, we get:

\frac{(x+2)(x+5)}{(x+3)}

The above is the simplest form of the given expression, \frac{x^2+7x+10}{x+3}

As we know that the denominator of a rational expression can never be zero, thus the only restriction in our case will be:

x+3\neq0

or, x\neq -3 (subtracting 3 from both sides)

Thus, the restriction is that x cannot be equal to -3.

Afina-wow [57]3 years ago
3 0
\cfrac{x^2+7x+10}{x+3 } =  \cfrac{ (x + 5)(x + 2)}{x + 3} , x  \neq -3
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I have 100 items of product in stock. The probability mass function for the product's demand D is P(D=90)=P(D=100)=P(D=110)=1/3.
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Answer:

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 96.667

The variance is 22.222

b) The probability mass function for the unfilled demand due to lack of stock is

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 3.333

The variance is 33.333

Step-by-step explanation:

If the demand is higher than 100, then you will sell 100 items only. Thus, there is a probability of 1/3+1/3 = 2/3 that you will sell 100 items, while there is a probability of 1/3 that you will sell 90.

The probability mass function for the items sold is

P_X(k) = \left \{ {\frac{1}{3} \, \, \, {k=90} \atop \, \frac{2}{3} \, \, \, {k=100}} \right.

The mean is 1/3 * 90 + 2/3 * 100 = 290/3 = 96.667

The variance is V(X) = E(X²)-E(X)² = (1/3*90² + 2/3*100²) - (290/3)² = 200/9 = 22.222

b) If order to be unfilled demand, you need to have a demand of 110, which happens with probability 1/3. In that case, the value of the variable, lets call it Y, that counts the amount of unfilled demand due to lack of stock is 110-100 = 10. In any other case, the value of Y is 0, which would happen with probability 1-1/3 = 2/3. Thus

P_Y(k) = \left \{ {\frac{2}{3} \, \, \, {k=0} \atop \, \frac{1}{3} \, \, \, {k=10}} \right.

The mean is 2/3 * 0 + 1/3 * 10 = 10/3 = 3.333

The variance is 2/3*0² + 1/3*10² = 100/3 = 33.333

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Answer:

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Step-by-step explanation:

Actually, you have a double root here:  {6, 6}:  "two real, equal roots."  That tells us immediately that the value of the discriminant was zero (0).

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