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krok68 [10]
3 years ago
8

Select all the statements that correctly describe the solutions to this system of equations?

Mathematics
1 answer:
Luba_88 [7]3 years ago
5 0

x + y = 9

x = 9 - y

2x - y = 0

2(9 - y) - y = 0

18 - 2y - y = 0

-3y = -18

y = 6

x = 9 - y

x = 9 - 6

x = 3

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Marianna [84]
6x 34 because you have to divide and then multi
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Consider the figure shown below. Find the value of BL
Gnesinka [82]

Answer:

BL = 2

Step-by-step explanation:

Given:

AL = 3

AC = 10

BC = 9

AL = AM = 3 (tangents drawn form am external point)

CM = AC - AM

CM = 10 - 3

CM = 7

CM = CN = 7 (tangents drawn form am external point)

BN = BC - CN

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BN = 2

BN = BL = 2 (tangents drawn form am external point).

BL = 2

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A certain virus infects one in every 200 people. a test used to detect the virus in a person is positive 70​% of the time when t
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We're told that

P(A)=\dfrac1{200}=0.005\implies P(A^C)=0.995

P(B\mid A)=0.7

P(B\mid A^C)=0.05

a. We want to find P(A\mid B). By definition of conditional probability,

P(A\mid B)=\dfrac{P(A\cap B)}{P(B)}

By the law of total probability,

P(B)=P(B\cap A)+P(B\cap A^C)=P(B\mid A)P(A)+P(B\mid A^C)P(A^C)

Then

P(A\mid B)=\dfrac{P(B\mid A)P(A)}{P(B\mid A)P(A)+P(B\mid A^C)P(A^C)}\approx0.0657

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b. We want to find P(A^C\mid B^C).

P(A^C\mid B^C)=\dfrac{P(A^C\cap B^C)}{P(B^C)}=\dfrac{P(B^C\mid A^C)P(A^C)}{1-P(B)}\approx0.9984

since P(B^C\mid A^C)=1-P(B\mid A^C).

4 0
3 years ago
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Answer:

38.46%

Step-by-step explanation:

There are no names or marking that can make the calculator look different, so the order is not important. Then we should use a combination to solve this problem.

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\frac{37}{19}* \frac{3}{1}= 37!\frac{37!}{19!(37-19!)} * \frac{3!}{1!(3-1)!}= 53017895700

The number of possible ways to choose 20 calculators out of 40 calculators will be:

\frac{40}{20}= \frac{40!}{20!(40-20!)}=137846528820

The chance will be: 53017895700/ 137846528820 = 0.3846= 38.46%

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Answer:

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