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3 years ago

What is the ultimate cause of wind on earth?

1 answer:

3 0

The ultimate cause of earth's winds is solar energy. when sunlight strikes Earth's surface,it heats that surface differently. Newly turned soil, for example,absorbs more heat than does snow. uneven heating of Earth's surface,in turn, cause difference in air pressure at various locations. heated air rises, creating an area of low pressure beneath. cooler air descends,creating an area of high pressure. since the atmosphere constantly seeks to restore balance,air from areas of high pressure always flow into adjacent areas of low pressure. this flow of air is wind. the difference in air pressure between two adjacent air masses over a horizontal ditance is called the pressure gradiant force. the greater the difference in pressure, the greater the difference pressure, the greater the force and tje stronger the wind

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what is your weight in newtons if your potential energy is equal to 1000 joules and your mass is 60 kg

Darina [25.2K]

Your potential energy and mass don't tell what your weight is.

If I walk up from the first floor to the second floor, my weight hasn't
changed even though my potential energy has increased.

6 0

4 years ago

Read 2 more answers

A plastic ball in a liquid is acted upon by its weight and by a buoyant force. The weight of the ball is 4 N. The buoyant force

Sauron [17]

Answer:

The acceleration is 2.448 meters per square second and is vertically upward.

Explanation:

The Free Body Diagram of the plastic ball in the liquid is presented in the image attached below. By Second Newton's Law, we know that forces acting on the plastic ball is:

$\Sigma F = F - m\cdot g = m\cdot a$ (1)

Where:

$F$ - Buoyant force, measured in newtons.

$m$ - Mass of the plastic ball, measured in kilograms.

$g$ - Gravitational acceleration, measured in meters per square second.

$a$ - Net acceleration, measured in meters per square second.

If we know that $F = 5\,N$ , $m = 0.408\,kg$ and $g = 9.807\,\frac{m}{s^{2}}$ , then the net acceleration of the plastic ball is:

$a = \frac{F}{m} - g$

$a= 2.448\,\frac{m}{s^{2}}$

The acceleration is 2.448 meters per square second and is vertically upward.

4 0

3 years ago

20.0 moles, 1840 g, of a nonvolatile solute, C 3H 8O 3 is added to a flask with an unknown amount of water and stirred. The solu

Anastasy [175]

Answer:

0.144 kg of water

Explanation:

From Raoult's law,

Mole fraction of solvent = vapor pressure of solution ÷ vapor pressure of solvent = 423 mmHg ÷ 528.8 mmHg = 0.8

Let the moles of solvent (water) be y

Moles of solute (C3H8O3) = 2 mole

Total moles of solution = moles of solvent + moles of solute = (y + 2) mol

Mole fraction of solvent = moles of solvent/total moles of solution

0.8 = y/(y + 2)

y = 0.8(y + 2)

y = 0.8y + 1.6

y - 0.8y = 1.6

0.2y = 1.6

y = 1.6/0.2 = 8

Moles of solvent (water) = 8 mol

Mass of water = moles of water × MW = 8 mol × 18 g/mol = 144 g = 144/1000 = 0.144 kg

7 0

3 years ago

A toy car moves around a circular track at constant speed. It suddenly doubles its speed — a change of a factor of 2. As a resul

Zigmanuir [339]

Answer:

option B

Explanation:

given,

toy car is moving in circular track

speed is doubled— a change of a factor of 2

to find change in factor of acceleration

radius doesn't change

centripetal acceleration formula

= $\dfrac{v^2}{r}$

velocity is change in factor of 2

so acceleration will be change at the factor of

= $\dfrac{(2v)^2}{r}$

= 2² = 4

so the correct answer is option B

4 0

4 years ago

A cylinder with moment of inertia I1 rotates with angular speed ω0 about a frictionless vertical axle. A second cylinder, with m

MAXImum [283]

Answer:

Part(a): The final angular velocity is $\omega_{f} = \dfrac{I_{1}\omega_{i}}{(I_{1} + I_{2})}$

Part(b): The ratio of the rotational energies is $\dfrac{k_{f}}{k_{i}}& = \dfrac{I_{1}}{(I_{1} + I_{2})}$ ,showing the the energy of th system will decrease.

Explanation:

Part(a):

If ' $I$ ' be the moment of inertia of an object and ' $\omega$ ' be its angular velocity then the angular momentum ' $L$ ' of the object can be written as

$L = I \omega$

If ' $I_{1}$ ' and ' $I_{2}$ ' be the moment of inertia of the two cylinders and ' $\omega_{1}$ ' and ' $\omega_{2}$ ' be the initial angular velocity of the cylinders and ' $\omega_{1}{'}$ ' and ' $\omega_{2}^'}$ ' be their respective final angular velocity, then from conservation of angular momentum,

$I_{1} \omega_{1} + I_{2} \omega_{2} = I_{1} \omega_{1}^{'} + I_{2} \omega_{2}^{'}$

Given, $\omega_{1} = \omega_{i},~\omega_{2} = 0,~\omega_{1}^{'} = \omega_{2}^{'} = \omega_{f}$ . From the above expression

$&& I_{1} \omega_{i} = (I_{1} + I_{2}) \omega_{f}\\&or,& \omega_{f} = \dfrac{I_{1}\omega_{i}}{(I_{1} + I_{2})}$

Part(b):

Initial kinetic energy

$K_{i} = \dfrac{1}{2} I_{1} \omega_{i}^{2}$

and Final kinetic energy

$K_{f} = \dfrac{1}{2}(I_{1} + I_{2}) \omega_{f}^{2}$

Substituting the value of $\omega_{f}$ ,

$&& K_{f} = \dfrac{1}{2}(I_{1} + I_{2})\dfrac{I_{1}^{2}\omega_{i}^{2}}{(I_{1} + I_{2})^{2}} = \dfrac{1}{(I_{1} + I_{2})} \dfrac{1}{2}I_{1}\omega_{i}^{2} = \dfrac{1}{(I_{1} + I_{2})} K_{i}\\&\dfrac{k_{f}}{k_{i}}& = \dfrac{I_{1}}{(I_{1} + I_{2})}$

The above expression shows that the ebergy of the system will decrease.

7 0

3 years ago