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DiKsa [7]
3 years ago
9

Need Help very important i will mark who gets this right brainiest.

Physics
1 answer:
Archy [21]3 years ago
7 0
Part f is lien seeing an alien and NAV meet up and explain to your teacher why they got it set up and then she will give u the answer
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Qualitative studies draw conclusions.<br> True<br> False
Marina86 [1]

Answer:

Hey there!

This is false. A qualitative study is about how a thing looks, not based on any mathematical or scientific data. Quantitative studies, on the other hand, draw conclusions.

Let me know if this helps :)

3 0
3 years ago
Apart from height above ground, what does the amount of gravitational potential energy that an object has on earth depend on?
damaskus [11]

Answer:

Gravitational potential energy is due to the position of an object above Earth's surface. The object has the potential to fall due to gravity.

Explanation:

Gravitational potential energy depends on an object's weight and its height above the ground (GPE = weight x height). hope this helps you :)

6 0
4 years ago
Read 2 more answers
Oki here are 3 questions! last one's!!
VashaNatasha [74]
Hi my friend I need points
4 0
2 years ago
Read 2 more answers
A child swings a tennis ball attached to a 0.626-m string in a horizontal circle above his head at a rate of 4.50 rev/s.
mr_godi [17]

Explanation:

Length of a string, l = 0.626 m

A tennis ball revolves in a horizontal circle above his head at a rate of 4.50 rev/s.

(a) The centripetal acceleration of the tennis ball is given by :

a=\omega^2r\\\\a=(4.5\times 2\pi)^2\times 0.626\\\\=500.44\ m/s^2

(b) When r = 0.626 m and ω = 4.50 rev/s

Speed,

v=r\omega\\\\=0.626\times 4.50 \times 2\pi\\\\=17.69\ m/s

When r = 1 m and ω = 4 rev/s

Speed,

v=r\omega\\\\=1\times 4 \times 2\pi\\\\=25.13\ m/s

Speed is more in second case when child now increases the length of the string to 1.00m but has to decrease the rate of rotation to 4.00 rev/s.

(c) a=\omega^2r\\\\a=(4\times 2\pi)^2\times 1\\\\=631.65\ m/s^2

Hence, this is the required solution.

5 0
3 years ago
Wagonium-292 has a half-life of 1 hour. If you started with an 80 gram sample, how much Wagonium-292 will remain after 4 hours?
viva [34]

After 1 hour, 80 g decays to 40 g.

After another hour (total 2 hours), 40 g decays to 20 g.

After another hour (total 3), 20 g decays to 10 g.

After one more hour (total 4), 10 g decays to (D) 5 g.

6 0
3 years ago
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