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4 years ago

How does friction,acceleration,speed and net force relate to each other?

1 answer:

8 0

Friction – the force that acts to resist the relative motion (or attempted motion) of objects or materials that are in contact
Acceleration – the change in velocity per certain time interval; how quickly motion changes
Net Force – the combination of all the forces that act on an object

Isaac Newton’s Second Law of Motion (F=ma) explains the relationship between force and acceleration in motion. The application of force on an object causes an acceleration of that object. Yet, force is not the only factor in the movement, or acceleration of an object. The two main influences on the acceleration of an object are net force and mass. For example, net force is directly proportional to acceleration while mass is inversely proportional to acceleration. In other words, net force- the force that has overcome friction and accelerates an object- is directly linked to acceleration; the more force you have, the faster an object goes.Other factors such as the friction, air or fluid resistance, and pressure effect the acceleration as well. All of these factors do not work against or in accordance with acceleration in the same way. Friction works in opposition to acceleration. Friction involves two objects that are in direct contact with on another but are moving in different directions. Involved with friction is air and fluid resistance. Fluid resistance, such as liquids or gases, focuses on when the object is moving in the opposite direction of a fluid flow or through a dense area of fluid. Air resistance involves movement through the air. The most noticeable effect of air resistance is when and object travels into a strong breeze or wind. And finally pressure, pressure refers to an applied force. With pressure you will find that the overall weight of and object doesn’t change no matter how you stand or lay it but you will fill more pressure from that same object depending on the force per surface area. The weight of the object has not changed but you that area of application the force feels greater. That is the pressure increase. In Newton’s Second Law, the areas such as free falling verse vacuum suction are also compared with the falling of objects.

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You are designing a rotating metal flywheel that will be used to store energy. The flywheel is to be a uniform disk with radius

Gennadij [26K]

Answer:

t = 0.0735 m

Explanation:

Angular acceleration of the flywheel is given as

$\alpha = 3 rad/s^2$

now after t = 8 s the speed of the flywheel is given as

$\omega = \alpha t$

$\omega = 3 \times 8$

$\omega = 24 rad/s$

now rotational kinetic energy of the wheel is given as

$K = \frac{1}{2}I\omega^2$

$K = \frac{1}{2}(\frac{1}{2}mR^2)(24^2)$

$800 = \frac{1}{4}m(0.23)^2(24^2)$

$m = 105 kg$

now we have

$m = \rho (\pi R^2) t$

$105 = 8600(\pi \times 0.23^2) t$

$t = 0.0735 m$

4 0

3 years ago

During the first 6 years of its operation, the Hubble Space Telescope circled the Earth 37,000 times, for a total of 1,280,000,0

madreJ [45]

Answer:

$Kilometers\ in\ 1\ Orbit=\frac{1.28*10^9 Km}{3.7*10^4orbits}$

$Kilometers\ in\ 1\ Orbit=3.46*10^4 Km/Orbit$

Explanation:

Given Data:

Numbers of times Telescope cycled around the earth in 6 years=37,000 times

Total Distance traveled in 6 years by the Hubble Space Telescope=1,280,000,000 Km

Find:

Kilometers in one Orbit=?

Solution:

Kilometers in 37,000 Orbits=1,280,000,000 Km

Kilometers in 1 Orbit=1,280,000,000/37,000

In Scientific Notation:

$Kilometers\ in\ 3.7*10^4\ Orbits=1.28*10^9 Km$

$Kilometers\ in\ 1\ Orbit=\frac{1.28*10^9 Km}{3.7*10^4 orbits}$

Kilometers in 1 Orbit=34594.594 Km

Kilometers in 1 Orbit in Scientific notation:

$Kilometers\ in\ 1\ Orbit=3.46*10^4 Km$

8 0

3 years ago

A softball is thrown from the origin of an x-y coordinate system with an initial speed of 18 m/s at an angle of 35∘ above the ho

podryga [215]

What we need to first do is split the ball's velocity into vertical and horizontal components. To do that multiply by the sin or cos depending upon if you're looking for the horizontal or vertical component. If you're uncertain as to which is which, look at the angle in relationship to 45 degrees. If the angle is less than 45 degrees, the larger value will be the horizontal speed, if the angle is greater than 45 degrees, the larger value will be the vertical speed. So let's calculate the velocities sin(35)*18 m/s = 0.573576436 * 18 m/s = 10.32437585 m/s cos(35)*18 m/s = 0.819152044 * 18 m/s = 14.7447368 m/s Since our angle is less than 45 degrees, the higher velocity is our horizontal velocity which is 14.7447368 m/s. To get the x positions for each moment in time, simply multiply the time by the horizontal speed. So 0.50 s * 14.7447368 m/s = 7.372368399 m 1.00 s * 14.7447368 m/s = 14.7447368 m 1.50 s * 14.7447368 m/s = 22.1171052 m 2.00 s * 14.7447368 m/s = 29.48947359 m Rounding the results to 1 decimal place gives 0.50 s = 7.4 m 1.00 s = 14.7 m 1.50 s = 22.1 m 2.00 s = 29.5 m

6 0

3 years ago

A bag of rocks has a mass of 16.4 kg what is it weight here on the earth

Alex73 [517]

Answer
160,72N
Explanation
W=mg
=(16.4)(9.8)

6 0

2 years ago

A lad, waiting for his friend walks in the sidewalk, in front of her house, from the front door, first, he moves towards the Pos

Andreas93 [3]

His total displacement from his original position is -1 m

We know that total displacement of an object from a position x to a position x', d = final position - initial position.

d = x' - x

If we assume the lad's initial position in front of her house is x = 0 m. The lad then moves towards the positive x-axis, 5 m. He then ends up at x' = 5 m. He then finally goes back 6 m.

Since displacement = final position - initial position, and his displacement is d' = -6 m (since he moves in the negative x - direction or moves back) from his initial position of x' = 5 m.

His final position, x" after moving back 6 m is gotten from

x" - x' = -6 m

x" = -6 + x'

x" = -6 + 5

x" = -1 m

Thus, his total displacement from his original position is

d = final position - initial position

d = x" - x

d = -1 m - 0 m

d = -1 m

So, his total displacement from his original position is -1 m

Learn more about displacement here:

brainly.com/question/17587058

3 0

3 years ago