Solution:
Number of times a die is rolled = 20
1 - 3=A
2 - 5=B
3 - 4=C
4 - 2=D
5 - 3=E
6 - 3=F
Total number of arrangements of outcomes , when a dice is rolled 20 times given that 1 appear 3 times, 2 appears 5 times, 3 appear 4 times, 4 appear 2 times , 5 appear three times, and 6 appear 3 times
= Arrangement of 6 numbers (A,B,C,D,E,F) in 6! ways and then arranging outcomes
= 6! × [ 3! × 5! × 4!×2!×3!×3!]
= 720 × 6×120×24×72→→[Keep in Mind →n!= n (n-1)(n-2)(n-3)........1]
= 895795200 Ways
Um i would love to help but i do t really understand
Answer:
M = 
Step-by-step explanation:
Given
w = 1000M - 200 ( isolate 1000M by adding 200 to both sides )
w + 200 = 1000M ( divide both sides by 1000 )
= M
Answer is C: 6/8
solve with square roots
Answer:
Step-by-step explanation:
We use formula of BODMAS we starting by removing blackets by multiply (2)(3)and w get 6 and then by 2 we get 12 and add by 5 we get 17 and cross 17 to -36 and 17 change to -17 and then take -17-36=-53..
-36=(2)(3)2+5
-36=(6)2+5
-36=12+5
-36=17
-17-36
=-53