Answer:
true
Explanation
1390. FMA. 24485. Anatomical terms of bone. The patella, also known as the kneecap, is a flat, rounded triangular bone which articulates with the femur (thigh bone) and covers and protects the anterior articular surface of the knee joint.
Here is the answer of the given problem above.
Use this formula: <span>P = FV = ma*at = ma^2 t
</span><span>Substitute the values, and therefore, we got m(a0)^2t = m(x)^2 (2t)
then, solve for x which is the acceleration at 2t.
</span>The <span>answer would be a0/sqrt(2).
Hope this answers your question. Thanks for posting.
</span>
Answer:
250cm or 2.5m
Explanation:
using direct variation
the length is = l
the time (year) = t
let k be the constant
so he have:
l=kt
2.5=k× 1
k= 2.5
Now in the next statement the 100 is given but not the length so
l=kt
~ l=k× 100 years
But k = 2.5
so :
l= 2.5×100
l= 250 cm
Hence it will be 250cm or 2.5m at which they will get separated
Answer:
The magnitude of the boy's displacement is 24.698 paces which is in the direction of approximately 58.24° North of East
Explanation:
The given parameters are;
The distance West the boy on a treasure hunt walks = 12 paces
The distance North the boy on a treasure hunt then walks = 21 paces
The distance East the boy on a treasure hunt then walks = 25 paces
Writing the displacement in vector format, gives;
d = -12·i + 21·j + 25·i
Which gives
d = 13·i + 21·j
The magnitude of the boy's resultant displacement is given as follows;
![\left | \mathbf{d} \right | = \sqrt{d_x^2 + d_y^2}](https://tex.z-dn.net/?f=%5Cleft%20%7C%20%5Cmathbf%7Bd%7D%20%5Cright%20%7C%20%3D%20%5Csqrt%7Bd_x%5E2%20%2B%20d_y%5E2%7D)
Where;
![d_x = 13, \ d_y = 21](https://tex.z-dn.net/?f=d_x%20%3D%2013%2C%20%5C%20d_y%20%3D%2021)
![\left | \mathbf{d} \right | = \sqrt{13^2 + 21^2} = \sqrt{610} \approx 24.698 \ paces](https://tex.z-dn.net/?f=%5Cleft%20%7C%20%5Cmathbf%7Bd%7D%20%5Cright%20%7C%20%3D%20%5Csqrt%7B13%5E2%20%2B%2021%5E2%7D%20%3D%20%5Csqrt%7B610%7D%20%20%5Capprox%2024.698%20%5C%20paces)
The magnitude of the boy's displacement is 24.698 paces
The direction of the displacement is tan⁻¹(21/13) ≈ 58.24° North of East.
Answer:
the second derivative of y with respect to time gives the transverse acceleration of an element on a string as a wave moves along an x axis along the string
Explanation:
This is because the transverse wave movement of particles take place in direction 90° to direction of movement of the wave (x) itself, so second derivative of y with respect to time (t)is what will be required