Answer:
41.02m
Explanation:
Given parameters:
Initial velocity = 0m/s
Final velocity = 96km/hr
Time taken = 3.07s
Unknown:
Distance traveled by the time the final speed was achieved = ?
Solution:
To solve this problem, we first find the acceleration of the car;
Acceleration =
v is the final velocity
u is the initial velocity
t is the time taken
Now convert the the final velocity to m/s;
96km/hr to m/s;
1 km/hr = 0.278m/s
96km/hr = 96 x 0.278 = 26.7m/s
Now;
Acceleration =
= 8.69m/s²
So;
v² = u² + 2as
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance
26.7² = 0² + 2 x 8.69 x s
712.89 = 17.38s
s = 41.02m
Answer:
Explanation:
Single-phase transformers can operate to either increasing or decreasing the voltage applied to the primary winding. When a transformer is used to “increase” the voltage on the secondary winding with respect to the primary, it is called a Step-up transformer
Decomposing - When plants and animals die, they decompose. This process uses up oxygen and releases carbon dioxide. Rusting - This is also called oxidation. When things rust they use up oxygen.
Because oil is a lubricant which reduces friction between our hands and glass. Less friction and it tends to slip so yes , it is related to friction
Answer:b)1770 kWh
Explanation:
Given
volume of water ![V=40,000 gallons](https://tex.z-dn.net/?f=V%3D40%2C000%20gallons)
Temperature rise ![\Delta T=10^{\circ}C](https://tex.z-dn.net/?f=%5CDelta%20T%3D10%5E%7B%5Ccirc%7DC)
![c=4186 J/kg-^{\circ} C](https://tex.z-dn.net/?f=c%3D4186%20J%2Fkg-%5E%7B%5Ccirc%7D%20C%20)
also 1 kg mass is approximately is 1 gallon
therefore 40,000 gallon is equivalent to 3.8\times 40000 kg
heat Required to raise temperature is
![Q=mc\Delta T](https://tex.z-dn.net/?f=Q%3Dmc%5CDelta%20T)
![Q=3.8\times 40000\times 4186\times 10](https://tex.z-dn.net/?f=Q%3D3.8%5Ctimes%2040000%5Ctimes%204186%5Ctimes%2010%20)
![Q=63,627.2\times 10^5 J](https://tex.z-dn.net/?f=Q%3D63%2C627.2%5Ctimes%2010%5E5%20J)
![Q=63,672.2\times 10^2 KJ](https://tex.z-dn.net/?f=Q%3D63%2C672.2%5Ctimes%2010%5E2%20KJ)
![Q=1767.42 kWh\approx 1770 kWh](https://tex.z-dn.net/?f=Q%3D1767.42%20kWh%5Capprox%201770%20kWh)