Answer:
when a element of 1 group take part in reaction, its atom looses outer electron and form positively charged ions called Cation.
Explanation:
High pressure
Low oxygen
Darkness
1) <span>yes;2
6*2=12
12*2=24
24*2=48
2)</span><span>Next Term (or nth term) = ar^n-1
</span>
a = first term, i.e. 5
<span>r = common ratio i.e. 3 (as 15/5=3 and 45/15=3 </span>
<span>n = .. </span>
<span>as you already have 1st , 2nd and 3rd terms</span>
<span>substituting now </span>
<span>T4= ar^n-1 </span>
<span>= 5*3^4-1 </span>
<span>= 5*3^3 </span>
<span>= 5*27 </span>
<span>T4 = 135
</span>T5= ar^n-1
<span>= 5*3^5-1 </span>
<span>= 5*3^4 </span>
<span>= 5*81 </span>
<span>T5 = 405 </span>
Answer:
83.3 kHz
Explanation:
The frequency of a waveform is equal to the reciprocal of its period:
![f=\frac{1}{T}](https://tex.z-dn.net/?f=f%3D%5Cfrac%7B1%7D%7BT%7D)
where
f is the frequency
T is the period
In this problem, we have
![T=12 \mu s=12\cdot 10^{-6} s](https://tex.z-dn.net/?f=T%3D12%20%5Cmu%20s%3D12%5Ccdot%2010%5E%7B-6%7D%20s)
so, the frequency of the waveform is
![f=\frac{1}{12 \cdot 10^{-6} s}=8.33\cdot 10^4 Hz](https://tex.z-dn.net/?f=f%3D%5Cfrac%7B1%7D%7B12%20%5Ccdot%2010%5E%7B-6%7D%20s%7D%3D8.33%5Ccdot%2010%5E4%20Hz)
And by converting into kiloHertz,
![f=8.33\cdot 10^4 Hz=83.3 kHz](https://tex.z-dn.net/?f=f%3D8.33%5Ccdot%2010%5E4%20Hz%3D83.3%20kHz)
Answer:
Explanation:
Equal to the sum of the densities of both substances
Equal to the sum of the densities of both substances
Equal to the difference in the densities of both substances
Equal to the difference in the densities of both substances
of which I cannot predict anything about its value
of which I cannot predict anything about its value
of an intermediate value to both substances which will depend on which substance is in greater quantity
of an intermediate value to both substances which will depend on which substance is in greater quantity