Your answer is D . Hope I helped :) !
1. The problem says that the television has a rectangular shape. So, the formula for caculate the area of a rectangle is:
A=LxW
"A" is the area of the rectangle (A=3456 inches²).
"L" is the the length of the rectangle.
"W" is the width of the rectangle.
2. The <span>width of the screen is 24 inches longer than the length. This can be expressed as below:
W=24+L
3. Then, you must substitute </span>W=24+L into the formula A=LxW:
<span>
</span>A=LxW
<span> 3456=L(24+L)
3456=24L+L</span>²
<span>
4. The quadratic equation is:
L</span>²+24L-3456=0
5. When you solve the quadratic equation, you obtain:
L=48 inches
6. Finally, you must substitute the value of the length, into W=24+L:
W=24+L
W=24+48
W=72 inches
7. Therefore, the dimensions of the screen are:
L=48 inches
W=72 inches<span> </span>
Answer:
sin(α) -cos(α)
Step-by-step explanation:

Let, the numbers = x, (x+2), (x+4)
x+x+2+x+4 = 63
3x+6=63
3x=57
x = 19
so, smallest number would be 19
Step-by-step explanation:
I4(-3)+5| +8(-3)
|-12+5| -24
7-24 = -17