Question

The pressure rise p associated with wind hitting a window of a building can be

Answer 1

Answer:

a)P=462.70 Pa

b)h = 0.047 m of water

Explanation:

Given that

Pressure ,$P=\dfrac{1}{2}\rho V^2$

$\rho = 1.2\ kg/m^3$

V= 100 km/h

$V=100\times \dfrac{1000}{3600}\ m/s$

V=27.77 m/s

The pressure P

$P=\dfrac{1}{2}\rho V^2$

$P=\dfrac{1}{2}\times 1.2\times 27.77^2\ Pa$

P=462.70 Pa

We know that density of the water $\rho=1000\ kg/m^3$

Lets height of the water column = h m

We know that

$_P=\rho _w g h$

462.70 = 1000 x 9.81 h

$h=\dfrac{462.7}{1000\times 9.81}\ m$

h = 0.047 m of water

a)P=462.70 Pa

b)h = 0.047 m of water