<span>Charles Darwin and Alfred Russel Wallace were the ones who had the idea of evolution in 1858!</span>
A bond with elements from B.
Become a physicist and maybe one day you can tell me.
The location of the point F that partitions a line segment from D to E (
), that goes from <u>negative 4</u> to <u>positive 5,</u> into a 5:6 ratio is fifteen halves (option 4).
We need to calculate the segment of the line DE to find the location of point F.
Since point D is located at <u>negative -4</u> and point E is at <u>positive 5</u>, we have:
Hence, the segment of the line DE () is 9.
Knowing that point F partitions the line segment from D to E () into a <u>5:6 ratio</u>, its location would be:
Therefore, the location of point F is fifteen halves (option 4).
Learn more about segments here:
I hope it helps you!
Explanation:
Elongation of the wire is:
ΔL = F L₀ / (E A)
where F is the force,
L₀ is the initial length,
E is Young's modulus,
and A is the cross sectional area.
ΔL = T (0.5 m) / ((2.0×10¹¹ Pa) (0.02 cm²) (1 m / 100 cm)²)
ΔL = T (1.25×10⁻⁶ m/N)
T = (80,000 N/m) ΔL
Draw a free body diagram of the mass at the bottom of the circle. There are two forces: tension force T pulling up and weight force mg pulling down.
Sum of forces in the centripetal direction:
∑F = ma
T − mg = mv²/r
T − mg = mω²r
T − (15 kg) (9.8 m/s²) = (15 kg) (2 rev/s × 2π rad/rev)² (0.5 m + ΔL)
T − 147 N = (2368.7 N/m) (0.5 m + ΔL)
Substitute:
(80,000 N/m) ΔL − 147 N = (2368.7 N/m) (0.5 m + ΔL)
(80,000 N/m) ΔL − 147 N = 1184.35 N + (2368.7 N/m) ΔL
(797631.3 N/m) ΔL = 1331.35 N
ΔL = 0.00167 m
ΔL = 1.67 mm
