Explanation:
Take north to be positive and south to be negative.
a = (v − v₀) / t
a = (-4.5 m/s − 4.5 m/s) / 8 s
a = -1.125 m/s²
The acceleration is 1.125 m/s² south.
The free fall of the phone is an uniformly accelerated motion toward the ground, with constant acceleration equal to
So, assuming the downward direction as positive direction of the motion, since the phone starts from rest the distance covered by the phone after a time t is given by
And if we substitute t=2.7 s, we find the distance covered:
Yes, that is true. I hoped I helped!
Answer:
a)
b)
Explanation:
From the question we are told that
Speed of opposing player
First player chase his opponent after
Acceleration of first player
Let time of catch be
a)Generally the Equation for distance covered is mathematically given as follows
Distance to catch First opponent
Distance to covered Second opponent
Generally when first opponent catch the second opponent it is represented mathematically as
b)Generally the the total time traveled by the first opponent is mathematically given as