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3 years ago

How many orders of magnitude (powers of ten) is the distance to the moon greater than the distance across the Atlantic ocean?

Physics

1 answer:

kupik [55]3 years ago

6 0

Answer:

The distance to the moon greater than the distance across the Atlantic ocean by an order of 1.

Explanation:

We have the average distance across the Atlantic ocean, $d_i=3700\ mi$

the average distance to the moon, $d_m=238,900\ mi$

The factor by which the distance to moon is greater than the width of Atlantic ocean:

$f=\frac{d_m}{d_i}$

$f=\frac{238,900}{3700}$

$f=64.57$

i.e.

the distance to the moon greater than the distance across the Atlantic ocean by an order of 1.

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Answer:

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Explanation:

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$\mathrm{F}=\mathrm{m} \times \mathrm{a}$

$\mathrm{F}=\mu \times \mathrm{m} \times \mathrm{g}$

Compare the above equation

$\mu \times m \times g=m \times a$

Cancel "m" common term in both L.H.S and R.H.S

$\text { Equation becomes, } \mu \times g=a$

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$\mathrm{g} \text { on earth surface }=9.8 \mathrm{m} / \mathrm{s}^{2}$

$\mu=\frac{2.25}{9.8}$

$\mu=0.229$

Hence coefficient of friction is 0.229.

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$\text { We know that } \mathrm{F}=\mathrm{m} \times \mathrm{a}$

$\mathrm{F}=2 \times 2.25 \quad(\mathrm{m}=2 \mathrm{kg} \text { given })$

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