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ki77a [65]
3 years ago
5

You have 6,000 with which to build a rectangular enclosure with fencing

Mathematics
1 answer:
Dominik [7]3 years ago
7 0
What is the question asking
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The coordinates of one endpoint of a line segment are (4, −12). The length of the segment is 5 units. Determine four coordinate
Nina [5.8K]

Answer:

Four coordinate pairs that could serve as the other endpoint of the given line segment are given by: (9,-12), (-1,-12), (4,-7), (4,-17).

Step-by-step explanation:

One endpoint of (4,-12), length of 5 units.

Four possible pairs:

Add 5 to x, keep y: (4+5,-12) = (9,-12).

Subtract 5 from x, keep y: (4-5,-12) = (-1,-12).

Keep x, add 5 to y: (4,-12+5) = (4,-7)

Keep x, subtract 5 from y: (4,-12-5) = (4,-17)

Four coordinate pairs that could serve as the other endpoint of the given line segment are given by: (9,-12), (-1,-12), (4,-7), (4,-17).

6 0
3 years ago
The solution of the system is (400, 3,200). How would you interpret this solution?
alekssr [168]
The solution (400, 3, 200) is the answer to a system of equations which has three variables. Respectively, this system is expected to have three equations because it has three unknowns. So for example if your unknowns are x, y and z, then the answers will be x=400, y=3, and z=200. 
3 0
3 years ago
Read 2 more answers
Solve<br> 5t &lt; -15 <br><br> T&lt; 3<br> T&lt; -3<br> T&gt; 3<br> T &gt; -3
OLga [1]

Answer:

B

Step-by-step explanation:

5t < -15 (divide by 5 on each side)

t < -3

7 0
3 years ago
Read 2 more answers
Assume that the population proportion is 0.56. Compute the standard error of the proportion, σp, for sample sizes of 100, 200, 5
Aliun [14]

Answer:

Standard errors are 0.049, 0.035, 0.022, and 0.016.

Step-by-step explanation:

The given value of population proportion (P) = 0.56

Given sample sizes (n ) 100, 200, 500, and 1000.

Now standard error is required to calculate.

Use the below formula to find standard error.

When sample size is n = 100

\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{100}} =0.049

When sample size is n = 200

\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{200}} = 0.035

When sample size is n = 500

\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{500}} =0.022

When sample size is n = 1000

\sqrt{\frac{P(1-P)}{n}} = \sqrt{\frac{0.56(1-0.56)}{1000}} = 0.016

4 0
3 years ago
Evaluate the following expression for c = - 3. - 3c² + c - 2c
Leno4ka [110]
When c = -3,
-3c² + c - 2c = -3c² - c
= -3(-3)² - (-3)
= -24
6 0
3 years ago
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